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zepelin [54]
3 years ago
9

Find the measure of angle b

Mathematics
2 answers:
galina1969 [7]3 years ago
3 0

Answer:

48. ..........hhshhxhxx

Step-by-step explanation:

180-42-90=48

Illusion [34]3 years ago
3 0
Angles on a straight line add to 180 degrees 42 + 90 because right angle =132 180-132=48 degrees
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Simplify (4xy)(2x2y)(3xy)3<br><br> 24x^2y^3<br> 24x^6y^5<br> 216x^3y^3<br> 216x^6y^5
Genrish500 [490]

Answer:

<u>The final answer is D. 216 x⁶ y⁵</u>

Step-by-step explanation:

Let's simplify the expression, this way:

1. Start with the coefficients:

4 * 2 * 3³

4 * 2 * 27

216

2. Variable x:

We have x * x² * x ³ = x¹⁺²⁺³ = x⁶

x⁶

3. Variable y:

We have y * y * y³ = y¹⁺¹⁺³ = y⁵

y⁵

4. Adding the pieces:

We put coefficients and variables together: 216 x⁶ y⁵

<u>The final answer is D. 216 x⁶ y⁵</u>

5 0
4 years ago
Read 2 more answers
You have $1.55 worth of dimes and nickels in a jar. There are 23 coins in the jar. How many dimes do you have? How many nickels
Scilla [17]

i believe the answer is 35 dimes and 65 nickels (sorry if i’m wrong lol)

3 0
3 years ago
How many positive integer factors of 100 are multiples of 2 or 3?
DedPeter [7]
<h3>Answer:</h3>
  • 6
<h3>Explanation:</h3>

The prime factorization of 100 is ...

... 100 = 2²×5²

The exponents of these factors are 2 and 2. Adding 1 to each of them and finding the product of those sums, we have ...

... (2+1)×(2+1) = 9

The number of divisors of 100 is 9. They are ...

... 1, 2, 4, 5, 10, 20, 25, 50, 100

Of these, 2, 4, 10, 20, 50, 100 are divisible by 2. That is, 6 factors of 100 are multiples of 2.

There are no multiples of 3 that are factors of 100, since 3 is not one of the prime factors.

7 0
3 years ago
Line that passes (4,2) &amp; (0,6)
mr Goodwill [35]

Answer:

y=-x+6

Step-by-step explanation:

8 0
3 years ago
Someone ans plz
alexira [117]

The GCF is mn^{4} p^{3}

Explanation:

The GCF or greatest common factor is the factorization of two or more numbers to determine the greatest number that they have common.

The given terms are m^{7} n^{4} p^{3} and m n^{12} p^{5}

To determine the gcf of these two terms, let us find the greatest number that they have in common.

Comparing the powers of m from both the terms, we have,

g c f\left(m^{7}, m\right)=m

Similarly, comparing the powers of n from both the terms, we have,

g c f\left(n^{4}, n^{12}\right)=n^{4}

Also, comparing the powers of p from both the terms, we have,

g c f\left(p^{3}, p^{5}\right)=p^{3}

Thus, the GCF of the terms m^{7} n^{4} p^{3} and m n^{12} p^{5} is mn^{4} p^{3}

8 0
3 years ago
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