All categories

2 years ago

What is the mass of 5.07 mol N2? (Answer)grams (3 SF)

Chemistry

1 answer:

Nata [24]2 years ago

5 0

Answer:

Mass, m = 141.96 kg

Explanation:

Given that,

Moles = 5.07

Molar mass of N₂ = 28 g/mol

We need to find the mass of 5.07 mol N₂.

We know that,

No of moles is equal to mass divided by molar mass i.e.

$n=\dfrac{m}{M}$

Where

m is mass of 5.07 mol of N₂

So,

$m=n\times M\\\\m=5.07\times 28\\\\m=141.96\ kg$

So, the required mass of 5.07 mol N₂ is 141.96 kg.

You might be interested in

A scientist evaluates its livestock and determines which livestock it is

Rina8888 [55]

Any animals look for steangth mostly because the offspring can probobly onther trait is looks. The male will try to impess the female.

4 0

3 years ago

What is the energy of light with a wavelength of 468 nm? (The speed of light

marshall27 [118]

The answer for the problem is explained below.

The option for the answer is "D".

Therefore the energy of the light is 4.25 × 10^-19 J

Explanation:

Given:

wavelength (λ) = 468 nm = 468×10^-9 m

speed of light (c) = 3.00 x 10^8m/s

Planck's constant is 6.626 x 10^-34J·s

To solve:

energy of light (E)

We know,

E =(h×c) ÷ λ

E = ( 6.626 x 10^-34 × 3.00 x 10^8) ÷ 468×10^-9

E = 4.25 × 10^-19 J

Therefore the energy of the light is 4.25 × 10^-19 J

6 0

2 years ago

4 HF(g)+SiO2(s) → SiF4(9)+2 H2O(9) Is the Si oxidized or reduced?

Airida [17]

Answer:

Si is reduced since it loses the oxygen atom

8 0

3 years ago

Calculate the electrical energy per gram of anode material for the following reaction at 298 K:

solmaris [256]

43.8 kJ

<h3>Explanation</h3>

There are two electrodes in a voltaic cell. Which one is the anode?

The lithium atom used to have no oxygen atoms when it was on the reactant side. It gains two oxygen atoms after the reaction. It has gained more oxygen atoms than the manganese atom. Gaining oxygen is oxidation. As a result, lithium is being oxidized.

Oxidation takes place at the anode of a cell. Therefore, the anode of this cell is made of lithium.

Lithium has an atomic mass of 6.94. Each gram of Li would contain 1/6.94 = 0.144 moles of Li atoms. Each Li atom loses one electron in this cell. Therefore, the number of electron transferred, n, equals 0.144 moles for each gram of the anode.

Let $w_\text{max}$ represents the electrical energy produced.