Question:
What is the area of the sector? Either enter an exact answer in terms of π or use 3.14 and enter your answer as a decimal rounded to the nearest hundredth.
Answer:
See Explanation
Step-by-step explanation:
The question is incomplete as the values of radius and central angle are not given.
However, I'll answer the question using the attached figure.
From the attached figure, the radius is 3 unit and the central angle is 120 degrees
The area of a sector is calculated as thus;
Where represents the central angle and r represents the radius
By substituting and r = 3
becomes
square units
Solving further to leave answer as a decimal; we have to substitute 3.14 for
So, becomes
square units
Hence, the area of the sector in the attached figure is or 9.42 square units
Answer:
a triangle always equals 180 degrees so
63+ 2x+8 + x+7 =180
solve for x
and then plug it back into original equation
let me know if this makes sense
glad to help you more if needed
Step-by-step explanation:
Answer:
idk you tell me
Step-by-step explanation:
1. you should tell me
2. i write the answer when you tell me
(√3 - <em>i </em>) / (√3 + <em>i</em> ) × (√3 - <em>i</em> ) / (√3 - <em>i</em> ) = (√3 - <em>i</em> )² / ((√3)² - <em>i</em> ²)
… = ((√3)² - 2√3 <em>i</em> + <em>i</em> ²) / (3 - <em>i</em> ²)
… = (3 - 2√3 <em>i</em> - 1) / (3 - (-1))
… = (2 - 2√3 <em>i</em> ) / 4
… = 1/2 - √3/2 <em>i</em>
… = √((1/2)² + (-√3/2)²) exp(<em>i</em> arctan((-√3/2)/(1/2))
… = exp(<em>i</em> arctan(-√3))
… = exp(-<em>i</em> arctan(√3))
… = exp(-<em>iπ</em>/3)
By DeMoivre's theorem,
[(√3 - <em>i </em>) / (√3 + <em>i</em> )]⁶ = exp(-6<em>iπ</em>/3) = exp(-2<em>iπ</em>) = 1
Step-by-step explanation:
pythagoras theorem: c²=a²+b²
Where c= longest side of a right angle triangle
AB= 6+r = c
AD= 12 =a
CD= r =b
(6+r)² = 12²+ r²
36+12r+r² =144 +r²
12r+r²-r²=144-36
12r=108
r= 108/12
r=9