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Damm [24]
3 years ago
11

Choose all the answers that apply.

Chemistry
2 answers:
pishuonlain [190]3 years ago
6 0
Has 7 neutrons is the answer
Katena32 [7]3 years ago
5 0

Answer:

has 7 neutrons

hope this helped.

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Which statement best describes a physical change?
Inga [223]

Answer:  3 Changes can occur to physical properties of a substance, but the chemical composition of the substance remains the same

Explanation:

Physical change mainly physical properties of a substance while the chemical changes remain unchanged. Once there is a change to the chemistry of the substance, this would be classified as a chemical change.

8 0
3 years ago
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Which is most likely an effect of long-term environmental changes
Alina [70]

Answer:

adaptation

extinction

speciation

Explanation:

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Someone anyone give me tips to finish online homework because i have 30 assignments to do
MrMuchimi

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Ok! I have four tips!

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Create A Time Table.

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6 0
3 years ago
The compound cisplatin, Pt(NH3)2Cl2, has been studied extensively as an antitumor agent.___K2PtCl4 (aq) + ___NH3 (aq)  ___Pt(NH
Lostsunrise [7]

Mass of cisplatin can be made : 144.6 g

<h3>Further explanation</h3>

Given

Reaction(unbalanced)

K2PtCl4 (aq) + ___NH3 (aq)  ___Pt(NH3)2Cl2 (s) + ___KCl (aq)

200 g of K2PtCl4

Required

mass of cisplatin  Pt(NH3)2Cl2

Solution

Balanced equation

K₂PtCl₄ (aq) + 2NH₃ (aq) ⇒Pt(NH₃)₂Cl₂ (s) + 2KCl (aq)

mol of K₂PtCl₄(MW=2.39+195+4.35.5=415 g/mol) :

mol = mass : Mw

mol = 200 : 415

mol = 0.482

From equation, mol ratio K₂PtCl₄ : Pt(NH₃)₂Cl₂ = 1 : 1, so mol Pt(NH₃)₂Cl₂ = 0.482

Mass of cisplatin Pt(NH₃)₂Cl₂(MW=195+2.14+6.1+2.35.5=300 g/mol) :

mass = mol x MW

mass = 0.482 x 300

mass = 144.6 g

8 0
3 years ago
A chemist pours 1 mol of zinc granules into one beaker and 1 mol of zinc chloride powder into another beaker. What do the two sa
Oksana_A [137]
Answer is: <span> two samples have in common same amount of substance and same number of particles.
1) There are same amount of substance in both beakers:
n(Zn) = 1 mol.
n(ZnCl</span>₂) = 1 mol.
2) There are same number of particles (atoms, molecules, ions) in both beakers:
N(Zn) = n(Zn) · Na.
N(Zn) = 1 mol · 6.023·10²³ 1/mol = 6.023·10²³ atoms of zinc.
N(ZnCl₂) = n(ZnCl₂) · Na.
N(ZnCl₂) = 1 mol · 6.023·10²³ 1/mol = 6.023·10²³ molecules of zinc(II) chloride.
Na - Avogadro number.


5 0
3 years ago
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