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BlackZzzverrR [31]
3 years ago
8

What is the maximum number of moles of NaCl that can be produced from the reaction of 5.6 mol Na and 4.7 mol CI2?

Chemistry
1 answer:
Gre4nikov [31]3 years ago
3 0

Answer:

Limiting - Na Excess - Cl2

Explanation:

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Perform the given operation and report the answer with the appropriate number of significant figures. 4.910 km - 0.08 km = ?
Digiron [165]

Answer:

4.83 km

Explanation:

Let's consider the following subtraction.

4.910 km - 0.08 km

For an addition or a subtraction, the rule for significant figures is as follows: <em>limit the reported answer to the rightmost column that all numbers have significant figures in common</em>, in this case, 2 figures after the decimal point.

4.910 km - 0.08 km = 4.83 km

5 0
3 years ago
Read the chemical equation. N2 + 3H2 → 2NH3 Using the volume ratio, determine how many liters of NH3 is produced if 1.2 liters o
zmey [24]

Answer : The volume of NH_3 produced will be, 0.8 liters.

Explanation : Given,

Volume of H_2 = 1.2 L

At STP, 1 mole of substance contains 22.4 L volume of substance.

The given balanced chemical reaction is:

N_2+3H_2\rightarrow 2NH_3

From the balanced chemical reaction we conclude that,

As, 3\times 22.4L volume of H_2 produced 2\times 22.4L volume of NH_3

So, 1.2L volume of H_2 produced \frac{2\times 22.4L}{3\times 22.4L}\times 1.2L=0.8L volume of NH_3

Therefore, the volume of NH_3 produced will be, 0.8 liters.

5 0
3 years ago
Read 2 more answers
If 29.4 mL of ethanol is dissolved in water to make 359 mL of solution, what is the concentration expressed in volume/volume % o
Sveta_85 [38]

Answer: 8.2\%

Explanation:- Volume percentage is the ratio of volume of solute to the volume of solution defined in terms of percentage.

{\text {volume percentage}}=\frac{\text {volume of solute}}{\text {volume of solution}}\times 100\%

Given: volume of solute = 29.4 ml

Volume of solution= 359 ml

{\text {volume percentage}=\frac{29.4}{359}\times 100\%=8.2\%


6 0
3 years ago
What does it mean for a chemical equation to be balanced?
Troyanec [42]

it is c because i did this with my teacher and we are doing about chemical atoms

7 0
3 years ago
The chemical equation below shows the formation of aluminum oxide (Al2O3) from aluminum (Al) and oxygen (O2).
Rufina [12.5K]

Answer:

Mass = 182.4 g

Explanation:

Given data:

Number of moles of Al₂O₃ = 3.80 mol

Mass of oxygen required = ?

Solution:

Chemical equation:

4Al + 3O₂    →       2Al₂O₃

Now we will compare the moles of aluminum oxide and oxygen.

                Al₂O₃           :           O₂

                   2               :            3

                 3.80            :         3/2×3.80 = 5.7

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 5.7 mol × 32 g/mol

Mass = 182.4 g

4 0
3 years ago
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