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Pachacha [2.7K]
3 years ago
12

In the combustion of ethane, shown above, how many moles of carbon dioxide can be produced from 1.00 mole of ethane? A. 0.500 mo

le B. 1.00 mole C. 2.00 moles D. 4.00 moles
Chemistry
1 answer:
Daniel [21]3 years ago
6 0
The balanced chemical equation for the <span>combustion of ethane is 
2C</span>₂H₆(g) + 7O₂(g) → 4CO₂(g) + 6H₂O(l)

The stoichiometric ratio between C₂H₆(g) and CO₂(g)  is 1 : 2

Hence,
    moles of 
CO₂(g) produced = moles of reacted C₂H₆(g) x 2
                                                 
= 1.00 mol x 2
                                                  = 2.00 mol

Hence, the correct answer is "C".
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A 31.0 mL sample of 0.624M perchloric acid is titrated with a 0.258M sodium hydroxide solution.
levacccp [35]

Answer:

0.0922 M

Explanation:

The problem first states that the titration is made using NaOH, and later asks about the addition of KOH. I'm going to assume NaOH was used throughout the whole problem. The result does not change if it was KOH instead.

The reaction that takes place is:

  • HClO₄ + NaOH → NaClO₄ + H₂O

First we <u>calculate how many HClO₄ moles are there in the sample</u>, using the <em>given molarity and volume</em>:

  • 0.624 M * 13.0 mL = 8.11 mmol HClO₄

Then we <u>calculate how many NaOH moles were added</u>:

  • 0.258 M * 15.0 mL = 3.87 mmol NaOH

Now we calculate how many HClO₄ remained after the reaction:

  • 8.11 - 3.87 = 4.24 mmol HClO₄

As <em>HClO₄ is a strong acid</em>, 4.24 mmol HClO₄ = 4.24 mmol H⁺

Finally we <u>calculate the molarity of H⁺</u>, using the<em> calculated number of moles and final volume</em>:

  • Final volume = 31.0 mL + 15.0 mL = 46.0 mL
  • 4.24 mmol / 46.0 mL = 0.0922 M
5 0
3 years ago
PLS HELP I WILL REWARD MOST BRAINLIEST
kvv77 [185]

Answer:

Actual yield = 138.94 g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2Na + Cl₂ —> 2NaCl

Next, we shall determine the mass of Na that reacted and the mass of NaCl produced from the balanced equation. This can be obtained as follow:

Molar mass of Na = 23 g/mol

Mass of Na from the balanced equation = 2 × 23 = 46 g

Molar mass of NaCl = 23 + 35.5

= 58.5 g/mol

Mass of NaCl from the balanced equation = 2 × 58.5 = 117 g

SUMMARY:

From the balanced equation above,

46 gof Na reacted to produce 117 g of NaCl.

Next, we shall determine the theoretical yield NaCl. This can be obtained as follow:

From the balanced equation above,

46 gof Na reacted to produce 117 g of NaCl.

Therefore, 57.50 g of Na will react to produce = (57.50 × 117)/46 = 146.25 g of NaCl.

Thus, the theoretical yield of NaCl is 146.25 g

Finally, we shall determine the actual yield of NaCl. This can be obtained as follow:

Percentage yield = 95%

Theoretical yield = 146.25 g

Actual yield =?

Percentage yield = Actual yield / Theoretical yield × 100

95% = Actual yield / 146.25

Cross multiply

Actual yield = 95% × 146.25

Actual yield = 95/100 × 146.25

Actual yield = 0.95 × 146.25

Actual yield = 138.94 g

4 0
3 years ago
Which model of the atom is thought to be true?
FinnZ [79.3K]

Answer:

Hi the answer should be B or 2

Explanation:

Hope this helps!

6 0
3 years ago
A reaction between liquid reactants takes place at in a sealed, evacuated vessel with a measured volume of . Measurements show t
Oxana [17]

This question is incomplete, the complete question;

A reaction between liquid reactants takes place at 16°C in a sealed, evacuated vessel with a measured volume of 10.0 L . Measurements show that the reaction produced 37.g of dinitrogen monoxide gas.

Calculate the pressure of dinitrogen monoxide gas in the reaction vessel after the reaction. You may ignore the volume of the liquid reactants. Round your answer to 2 significant digits.

Answer:

Explanation:

Given that;

Volume = 10.0 L

Temperature T = 16°C = ( 16 + 273) = 289 K

we know that  molar mass of N₂O = 44 g/mol

number number of moles n will be: weight/molar mass = 37/44 = 0.8409 moles

Universal Gas constant R = 0.0821 atm.mol⁻¹.k⁻¹

pressure p = ?

from the ideal gas law

PV = nRT

P = nRT / n

so we substitute

P = (0.8409 mole × 0.0821 atm.mol⁻¹.k⁻¹ × 289 K) / 10.0 l

P = 19.95195 / 10.0

P = 1.9952 atm

6 0
3 years ago
"write the chemical equation between hydrogen (h) and carbonate (CO3) and the product(s)"<br>​
olga2289 [7]

Answer:

On heating sodium hydrogen carbonate (NaHCO3). It decomposes to form sodium carbonate (Na2CO3), water (H2O) and carbon dioxide (CO2)

(ii) 2NaHCO3(s)Heatsodiumcarbonate(sodaash)Na2CO3(s)+CO2(g)+H2O(l)

8 0
2 years ago
Read 2 more answers
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