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Pachacha [2.7K]
3 years ago
12

In the combustion of ethane, shown above, how many moles of carbon dioxide can be produced from 1.00 mole of ethane? A. 0.500 mo

le B. 1.00 mole C. 2.00 moles D. 4.00 moles
Chemistry
1 answer:
Daniel [21]3 years ago
6 0
The balanced chemical equation for the <span>combustion of ethane is 
2C</span>₂H₆(g) + 7O₂(g) → 4CO₂(g) + 6H₂O(l)

The stoichiometric ratio between C₂H₆(g) and CO₂(g)  is 1 : 2

Hence,
    moles of 
CO₂(g) produced = moles of reacted C₂H₆(g) x 2
                                                 
= 1.00 mol x 2
                                                  = 2.00 mol

Hence, the correct answer is "C".
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How many grams are in 3.14 x 1015 molecules of CO?
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1 mol of CO has a mass of

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O = 16

1 mol = 28 grams.

1 mol of molecules = 6.02 * 10^23

x mol of molecules = 3.14 * 10^15        Cross multiply

6.02*10^23 x = 1 * 3.14 * 10^15             Divide by 6.02*10^23

x = 3.14*10^15 / 6.02*10^23

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x = 5*10^-9

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5*10^-9 mol of CO has a mass of x                        Cross Multiply

x = 5 * 10^-9 * 28

x = 1.46 * 10^-7 grams

Answer: there are 1.46 * 10-7 grams of CO if only 3.14 * 10^15 molecules are in the sample

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