Moles = n = 3.91 mol
Pressure = P = 5.35 atm
Temperature = T = 323 K
Volume = V = ?
Formula used: Ideal Gas Equation is used,
P V = n R T
Solving for V,
V = n R T / P
Putting Values,
V = (3.91 mol × 0.0825 atm.L.mol⁻¹.K⁻¹ × 323 K) ÷ 5.35 atm
V = 19.36 L
Answer is: 588.15 <span>grams of ethanol.
</span>Chemical reaction: C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂.
m(C₆H₁₂O₆) = 1150 g.
n(C₆H₁₂O₆) = m(C₆H₁₂O₆) ÷ M(C₆H₁₂O₆).
n(C₆H₁₂O₆) = 1150 g ÷ 180.16 g/mol.
n(C₆H₁₂O₆) = 6.38 mol.
From chemical reaction: n(C₆H₁₂O₆) : n(C₂H₅OH) = 1 : 2.
n(C₂H₅OH) = 12.76 mol.
m(C₂H₅OH) = 12.76 mol · 46.07 g/mol.
m(C₂H₅OH) = 588.15 g.
Answer: The statement is false
Explanation:
Electrons occupy a region in atoms known as orbitals or subs hell. These orbitals include
I) S-orbital: it can occupy a maximum of two electrons
II) P-orbital: It occupies a maximum of six electrons
III) D-orbital: it occupies a maximum of ten electrons
F and G-orbitals as examples of other orbitals present.
A good illustration of the 6 electrons occupied by the P-subshell is seen in Sodium (Na) with atomic number of 11
Na = 1s2, 2S2 2p6, 3s1
Note: extra electrons are transferred to the next orbital
