Answer:(10.69, 11.436)
Explanation:
Given
initial height of ball is 2 m
height of basket is 3.05 m
Launching angle
y=1.05
equation of trajectory of ball is given by
for x=12.27
u=10.69
for x=11.73
u=11.436 m/s
Thus range of speed is (10.69, 11.436)
F/18=2/3
F=2×18/3
F=12N