Answer:
The first one is graph and the second one is electronic balance, third computer then data table and the last is graduated cylinder.
Explanation:
cuz i got it right
Answer:
Magnetic force, F = 0.24 N
Explanation:
It is given that,
Current flowing in the wire, I = 4 A
Length of the wire, L = 20 cm = 0.2 m
Magnetic field, B = 0.6 T
Angle between force and the magnetic field, θ = 30°. The magnetic force is given by :
F = 0.24 N
So, the force on the wire at an angle of 30° with respect to the field is 0.24 N. Hence, this is the required solution.
D, small force for short time, as it has the least influence on the velocity.
C, momentum is velocity x mass, so if velocities are the same, then the object with less mass with have a lower momentum.
Answer: 2.9kg
let mass be=m ; F=15N; Sin(theta)=32°;g =9.8kgm/s^2.
represent the mass. By resolving forces, we have:
F=mgSin(theta)
15N=mgSin(32°)
m=15N/g×Sin(32°)
m=15N/9.8m/s^2÷Sin(32°)
=2.888kg2.888
≈2.9kg
It starts at B. the center circle
