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3 years ago

7

A pivot at the 35cm mark supports a meter stick. It is brought into a balance by a 0.85N weight suspended at the 5.5cm mark.comp

ute the weight of the meter stick.

1 answer:

Arte-miy333 [17]3 years ago

8 0

Answer:

2.52N

Explanation:

according to law of moments ,

F1L1=F2L2 ,where the forces are in equilibrium .

0.85(44.5)= 15F2

that is , taking their distances from 50cm point

37 .825=15F2

37.825÷15= F2

2.52N = F2

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$KE=1.2036\times 10^{-12}\ J$

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