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Tems11 [23]
2 years ago
8

A. What are the coordinates of the vertices of the triangle below?

Mathematics
1 answer:
Viktor [21]2 years ago
4 0

Answer:

Solution given:

<u>A.coordinate are</u>

A(-2,3)

B(0,-3)

C(4,5)

<u>B</u><u>.</u><u>Each</u><u> </u><u>length</u><u> </u><u>are</u><u> </u><u>:</u>

we have

length \sqrt{(x2-x1)²+(y2-y1)²}

now

AB:\sqrt{(-2-0)²+(3+3)²}=2\sqrt{10}units

BC:\sqrt{(0-4)²+(-3-5)²}=4\sqrt{5}units

AC:\sqrt{(-2-4)²+(3-5)²}=2\sqrt{10}units

<u>C.</u><u> the </u><u>figure</u><u>:</u>

<u>By</u><u> </u><u>using</u><u> </u><u>Pythagoras</u><u> </u><u>law</u>

base[b]=AB=perpendicular [p]=AC

hypotenuse [h]=BC

we have

h²=p²+b²

substituting value

(4\sqrt{5})²=2p²

16*5=2*(2\sqrt{10})²

80=2*4*10

80=80

<u>SO</u><u> </u><u>IT</u><u> </u><u>IS</u><u> </u><u>RIGHT</u><u> </u><u>ANGLED</u><u> </u><u>ISOSCELES</u><u> </u><u>TRIANGLE</u><u>.</u>

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