C. oxidation of<span> hydrogen sulfide from the vent water
is the answer.</span>
Answer:
Explanation:
We need to convert 
to 
So
The speed of the gas molecules is .
Answer:
0.84kg of gatorade powder
Explanation:
From the question given, we were told that 0.6kg of gatorade powder required 5 gallons of water.
To obtain the mass of gatorade needed for 7 gallons of water, we simply do the following:
0.6kg of gatorade powder required 5 gallons of water.
Therefore, xkg of gatorade powder will require 7 gallons of water i.e
xkg of gatorade powder = (0.6 x 7)/5
xkg of gatorade powder = 0.84kg
Therefore, 0.84kg of gatorade powder will be required.
The easiest way to answer this question is to first figure out the molar mass of the sugar in question. To do this multiply the number of individual atoms for a given element by its atomic mass. 12 X 12.01 g/mol = 144.12 g/mol C. 22 X 1.008 g/mol = 22.176 g/mol H. 11 X 16.00 g/mol = 176.00 g/mol O.
Answer:
* 
* 
* 
Explanation:
Hello,
In this case, for the mole fraction of methanol we use the formula:
Thus, we compute the moles of both water (molar mass 18 g/mol) and methanol (molar mass 32 g/mol):
Hence, mole fraction is:
Next, mass percent is:
And the molality, considering the mass of water in kg (0.185 kg):
Regards.
