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3 years ago

Yoooo help me w this one

Chemistry

1 answer:

Scilla [17]3 years ago

6 0

Answer:

0.84kg of gatorade powder

Explanation:

From the question given, we were told that 0.6kg of gatorade powder required 5 gallons of water.

To obtain the mass of gatorade needed for 7 gallons of water, we simply do the following:

0.6kg of gatorade powder required 5 gallons of water.

Therefore, xkg of gatorade powder will require 7 gallons of water i.e

xkg of gatorade powder = (0.6 x 7)/5

xkg of gatorade powder = 0.84kg

Therefore, 0.84kg of gatorade powder will be required.

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Provide an explanation that is grounded in polarity that better explains why oil is not miscible in vinegar.

butalik [34]

Explanation:

Vinegar is a sour liquid made up of acetic acid compounds. Oil is a complex non-polar chemical compound with a high amount of hydrogen and carbon in its structure.

Vinegar is a polar acid, although a weak one.
Generally, for a substance to mix with another one, they must be similar.
Solubility of compounds controls miscibility.
When two substances are miscible, they can be said to be soluble in one another.
In solubility, like substances dissolves like substances.
This implies that polar compounds will only dissolve polar compounds.
Non-polar compounds will only dissolve in non-polar solvents.
Since vinegar is polar and oil is non-polar, they will not dissolve one another.

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3 years ago

What is the mass of 8.23 x 10^23 atoms of Ag

Gnom [1K]

Answer:

$\boxed {\boxed {\sf Approximately \ 147 \ g\ Ag}}$

Explanation:

Convert Atoms to Moles

The first step is to convert atoms to moles. 1 mole of every substance has the same number of particles: 6.022 ×10²³ or Avogadro's Number. The type of particle can be different, in this case it is atoms of silver. Let's create a ratio using this information.

$\frac{6.022*10^{23} \ atoms \ Ag}{1 \ mol \ Ag}$

We are trying to find the mass of 8.23 ×10²³ silver atoms, so we multiply by that number.

$8.23 *10^{23} \ atoms \ Ag *\frac{6.022*10^{23} \ atoms \ Ag}{1 \ mol \ Ag}$

Flip the ratio so the atoms of silver cancel. The ratio is equivalent, but places the other value with units "atoms Ag" in the denominator.

$8.23 *10^{23} \ atoms \ Ag *\frac{1 \ mol \ Ag}{6.022*10^{23} \ atoms \ Ag}$

$8.23 *10^{23} *\frac{1 \ mol \ Ag}{6.022*10^{23} }$

Condense into one fraction.

$\frac{8.23 *10^{23} }{6.022*10^{23} } \ mol \ Ag$

$1.366655596 \ mol \ Ag$

Convert Moles to Grams

The next step is to convert the moles to grams. This uses the molar mass, which is equivalent to the atomic mass on the Periodic Table, but the units are grams per mole.