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andrew11 [14]
2 years ago
11

Julie has four times as many pairs of shoes as her brother. Together they have 15 pairs of shoes. How many pairs of shoes do the

y each have?
Mathematics
2 answers:
krek1111 [17]2 years ago
5 0

Answer:

60 pairs of shoes

Step-by-step explanation:

To find the answer, multiply 4x15. The words four times as many mean to do the operation of multiplication. 4x15= 60 So finally, each have 60 pairs of shoes.

<em>i</em><em> </em><em>hope</em><em> </em><em>this</em><em> </em><em>helped</em><em>:</em><em>)</em>

marshall27 [118]2 years ago
4 0

Answer:

7.5

Step-by-step:

Julie: ?

Her brother: ?

Total number: 15

So: 15 divided to julie and her brother-

There for 15 divide by 2 is 7.5

7.5+7.5=<u>15</u>

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(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

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p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

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2 years ago
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