The correct answer to the question is : A) The velocity of the cart after it hits the wall.
EXPLANATION:
Before answering this question, first we have to understand impulse.
Impulse of a body is defined as the change in momentum or the product of force with time.
Mathematically impulse = m ( v- u ).
Here, v is the final momentum and u is the initial momentum.
Hence, we need the velocity of the cart after it hits the wall in order to calculate the impulse of the lab cart.
Answer:
28.7%
Explanation:
efficiency = work output /work input × 100
Answer:
351 ohm
720 ohm
Explanation:
When c and d are open:
Terminals c and d are open.. If you redraw the circuit as below, you can see that the two resistors in the first column are in parallel as, they are connected together at both pairs of terminals (due to the short).
Hence, we have a pair of parallel resistors:
Req1 = (R1*R2)/ (R1 + R2) = 360*540/(360+540) = 216 ohms
Req2 = (R3*R4)/ (R3 + R4) = 180*540/(180+540) = 135 ohms
Now these two sets are in series with another Hence,
Req = Req1 + Req2 = 216 + 135 = 351 ohms
Answer: 351 ohms
When c and d are shorted:
The current will flow through the least resistant path naturally from resistors R3 and R1 or R4.
Both of these resistor lie in a single path placing the resistors in series to one another, hence
Req = R3 + R1 = 180 + 540 = 720 ohms
Answer:720 ohms
That's true.
I have a hunch that there definitely IS a change of phase at every reflection.
