**Answer:**

**She travels **<u>**6.94 m**</u>** before stopping.**

**Explanation:**

Given:

Initial velocity of the skier (u) = 5.47 m/s

Final velocity of the skier (v) = 0 m/s (Comes to stop)

Coefficient of kinetic friction (μ) 0.220

**Let the mass of skier be 'm', acceleration of the skier be 'a' and the distance traveled be 'd' before coming to a stop.**

Now, using the **equation of motion** as:

Plugging in the given values and expressing 'a' in terms of 'd', we get:

Now, the above acceleration is due to the frictional force. Now, frictional force is given as:

-------------- (2)

Here,** 'N' is the normal force which is equal to the weight of the skier.**

From** Newton's second law, frictional force is equal to the product of mass and acceleration.** Here, **friction acts in the opposite direction** to motion.

So, ---------- (3)

**Equating equations (2) and (3),** we get:

Therefore, **she travels 6.94 m before stopping.**