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kobusy [5.1K]
3 years ago
13

Leila drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 10 hours. When Leila drov

e home, there was no traffic and the trip only took 7 hours. If her average rate was 18 miles per hour faster on the trip home, how far away does Leila live from the mountains?
Physics
1 answer:
9966 [12]3 years ago
5 0

Answer:

420 miles

Explanation:

Since distance is speed times time taken, you get two conditions:

\left \{ {{d=v*10} \atop {d=(v+18)*7}} \right.

Easiest way to solve it is to set the two condition equal - she's coming and going from the same place after all - and you get 10v=(v+18)*7\\10v=7v+3*6*7\\3v=3*6*7 \\v=42 Replace in either equation and you'll get d=420

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Find the fundamental frequency and the next three frequencies that could cause standing-wave patterns on a string that is 30.0 m
maksim [4K]

Answer:

0.786 Hz, 1.572 Hz, 2.358 Hz, 3.144 Hz

Explanation:

The fundamental frequency of a standing wave on a string is given by

f=\frac{1}{2L}\sqrt{\frac{T}{\mu}}

where

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For the string in the problem,

L = 30.0 m

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Substituting into the equation, we find the fundamental frequency:

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So we get:

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f_3 = 3 (0.786 Hz)=2.358 Hz

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