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kobusy [5.1K]
3 years ago
13

Leila drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 10 hours. When Leila drov

e home, there was no traffic and the trip only took 7 hours. If her average rate was 18 miles per hour faster on the trip home, how far away does Leila live from the mountains?
Physics
1 answer:
9966 [12]3 years ago
5 0

Answer:

420 miles

Explanation:

Since distance is speed times time taken, you get two conditions:

\left \{ {{d=v*10} \atop {d=(v+18)*7}} \right.

Easiest way to solve it is to set the two condition equal - she's coming and going from the same place after all - and you get 10v=(v+18)*7\\10v=7v+3*6*7\\3v=3*6*7 \\v=42 Replace in either equation and you'll get d=420

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3 years ago
A 94 g particle undergoes SHM with an amplitude of 8.3 mm, a maximum acceleration of magnitude 7.8 x 103 m/s2, and an unknown ph
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Answer:

a) T = 6.49*10^-3 s

b) v = 8 m/s

c) E = 3 J

d) F = 733 N

e) F = 366.5 J

Explanation:

Given

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Amplitude of the particle, A = 8.3 mm = 8.3*10^-3 m

Maximum acceleration of particle, a = 7.8*10^3 m/s²

the equation describing Simple Harmonic Motion is given as

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To fond the acceleration of this relationship, we would have to integrate. Twice, the first would be a Velocity, and the second acceleration that we need.

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Acceleration = d²x/dt = -Aw² cos(wt + φ)

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w² = 7.8*10^3 / 8.3*10^-3

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Maximum speed = 8.0 m/s

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For x to be maximum here, then cos(wt + φ) Must be equal to 1

Acceleration = d²x/dt² = -Aw²

And force = mass * acceleration

Force = 0.094 * 7.8*10^3

Force = 733 N

x = A cos(wt + φ), where cos(wt + φ) = 1/2

d²x/dt² = -Aw² * 1/2

d²x/dt² = 733 * 0.5

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