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Sedbober [7]
3 years ago
13

Function Of The glottis​

Physics
2 answers:
Cloud [144]3 years ago
8 0

Answer:

Their function is to produce sound by allowing the free edges of the folds to vibrate against one another and also to act as the laryngeal sphincter when they are closed.

Lunna [17]3 years ago
7 0
Answer:

The glottis is found within the larynx, and the epiglottis is a flap-like structure on top of the trachea. When swallowing, it will press downward to partially close off the trachea. Function of the glottis and epiglottis do to help prevent food and liquid from entering the air passage (trachea)

Can I please get brainliest
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A circle has an initial radius of 50ft when the radius begins decreasing at a rate of 2ft/s. what is the rate of change of the a
valkas [14]
The area of the circle with radius r is
A = πr²

The rate of change of area with respect to time is
\frac{dA}{dt} = \frac{dA}{dr} . \frac{dr}{dt} =2 \pi r. \frac{dr}{dt}

The rate of change of the radius is given as
\frac{dr}{dt} =-2 \,  \frac{ft}{s}
Therefore
\frac{dA}{dt} =-4 \pi r \,  \frac{ft^{2}}{s}

When r = 10 ft, obtain
\frac{dA}{dt}|_{r=10 \, ft} = -40 \pi  \,  \frac{ft^{2}}{s}

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7 0
3 years ago
A race car circles 10 times around a circular 8.0-km track in 20 min.
Otrada [13]
Find the average speed and the average velocity.

Average speed = distance / time

distance = 10 x 8000 m = 80,000 m
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Average velocity = displacement / time

Given that the race car made complete circles the final poin is the same initial point, then its displacement is zero and the average velocity is zero too.
6 0
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2 years ago
In the diagram, q1, q2, and q3 are in a straight line.
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A red laser from the physics lab is marked as producing 632.8-nm light. When light from this laser falls on two closely spaced s
BARSIC [14]

Answer:

The wavelength is  \lambda_R  =  649 *10^{-9}\ m

Explanation:

From the question we are told that

   The wavelength of the red laser is  \lambda_r  =  632.8 \ nm =  632.8 *10^{-9}\ m

    The spacing between  the fringe is  y_r  =  6.00\ mm =  6.00*10^{-3}  \  m

   The spacing between  the fringe for smaller laser point  is  y_R   = 6.19 \ mm =  6.19 *10^{-3} \  m

      Generally the spacing between  the fringe is mathematically represented as

       y  =  \frac{D *  \lambda  }{d}

Here  D is the distance to the screen

    and  d is the distance of the slit separation

Now for both laser red light light and  small laser  point  D and  d are same for this experiment

So

         \frac{y_r}{\lambda_r}  =  \frac{D}{d}

=>      \frac{y_r}{\lambda_r}  = \frac{y_R}{\lambda_R}

Where \lambda_R  is the wavelength produced by the small laser pointer

  So

           \frac{6.0 *10^{-3}}{ 632.8*10^{-9}}  = \frac{ 6.15 *10^{-9}}{\lambda_R}

=>       \lambda_R  =  649 *10^{-9}\ m

7 0
3 years ago
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