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Ludmilka [50]
2 years ago
11

Water pours into a fish tank at a rate of 0.3 cubic meters per minute. How fast is the water level rising if the base of the fis

h tank is a 2 meter by 3 meter rectangle?
Physics
1 answer:
Olin [163]2 years ago
5 0

Answer:

\frac{dh}{dt} = 0.05 m/min

Explanation:

As we know that the dimensions of the base of the tank is given as

L = 2 m

W = 3 m

now the base area is given as

A = 2m \times 3 m

A = 6 m^2

now we know that volume of the liquid filled in the tank is given as

V = Area \times height

V = 6 \times h

now we will differentiate it with respect to time both sides

\frac{dV}{dt} = 6 \times \frac{dh}{dt}

here we know that

\frac{dV}{dt} = 0.3 m^3/min

now we have

0.3 m^3/min = (6 m^2) \frac{dh}{dt}

\frac{dh}{dt} = 0.05 m/min

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