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Ludmilka [50]
3 years ago
11

Water pours into a fish tank at a rate of 0.3 cubic meters per minute. How fast is the water level rising if the base of the fis

h tank is a 2 meter by 3 meter rectangle?
Physics
1 answer:
Olin [163]3 years ago
5 0

Answer:

\frac{dh}{dt} = 0.05 m/min

Explanation:

As we know that the dimensions of the base of the tank is given as

L = 2 m

W = 3 m

now the base area is given as

A = 2m \times 3 m

A = 6 m^2

now we know that volume of the liquid filled in the tank is given as

V = Area \times height

V = 6 \times h

now we will differentiate it with respect to time both sides

\frac{dV}{dt} = 6 \times \frac{dh}{dt}

here we know that

\frac{dV}{dt} = 0.3 m^3/min

now we have

0.3 m^3/min = (6 m^2) \frac{dh}{dt}

\frac{dh}{dt} = 0.05 m/min

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Answer:

<em>The person delivered a power of 2,558 Watt</em>

Explanation:

<u>Work and Power</u>

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If both the force and displacement are parallel, then we can use the equivalent scalar formula:

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Power is the amount of energy transferred per unit of time. In the SI, the unit of power is the watt, equivalent to one joule per second.

The power can be calculated as:

\displaystyle P=\frac {W}{t}

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The work done when lifting the weight 7 times by a distance of s=2.2 m is:

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