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alex41 [277]
2 years ago
12

B^2-5b+3 for b=-3 plz help​

Mathematics
1 answer:
nika2105 [10]2 years ago
3 0

Hey there!

b^2 - 5b + 3

= -3^2 - 5(-3) + 3

= -9 - (-15) + 3

= -9 + 15 + 3

= 6 + 3

= 9

Answer: 9

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

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Answer:

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Step-by-step explanation:

In right triangle MNP, MP = 4 cm, m∠N = 90°, m∠P = 21°

By the sine definition,

\sin \angle P=\dfrac{\text{Opposite leg}}{\text{Hypotenuse}}=\dfrac{MN}{MP}\\ \\MN=MP\sin \angle P\\ \\MN=4\sin 21^{\circ}\approx 1.43\ cm

Now, consider right triangle HMN (it is right because NH is an altitude). By the cosine definition,

\cos \angle M=\dfrac{\text{Adjacent leg}}{\text{Hypotenuse}}=\dfrac{MH}{MN}\\ \\MH=MN\cos \angle M

In the right triangle, two acute angles are always complementary, so

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MH=1.43\cos 69^{\circ}\approx 0.51\ cm

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