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Svetlanka [38]
3 years ago
12

Marty is making a layaway purchase of a $1,500 couch at Frank’s Furniture Store. He will be paying $156 every 2 weeks for 20 wee

ks on a layaway plan. What is the layaway fee for this purchase?
Mathematics
1 answer:
Burka [1]3 years ago
6 0

Answer:

$60

Step-by-step explanation:

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GEOMETRY HELP PLEASE!! WILL MARK BRAINLEIST!<br> 5
adell [148]

AC=BD

64 units=10x+24

64-24=10x

40=10x

X=40 divided by 10= 4

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3 years ago
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Write a real-world problem given the equation 2/3x = 12. Then solve the equation.
LuckyWell [14K]

Answer:

x = 1/18

Step-by-step explanation:

2/3x = 12

multiply both sides by 3x

2/3x(3x) = 12(3x)

2 = 36x

x = 1/18

5 0
3 years ago
How do i explain how the distance on the number line and opposit numbers are related
strojnjashka [21]
Hey there!

The distance on a number line is the distance that a point is from 0.
For example, if you were looking at a number line and there was a point on the number 5, that point would be 5 units away from 0.

Opposite numbers are related because they are the same distance away from 0. For example -3 and 3 are both 3 units away from the number 0.

I hope this helped! :-)
7 0
3 years ago
Expand the following question 3(3x-2)
marissa [1.9K]

3(3x - 2)

Distribute (multiply) 2 inside the parentheses.

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9x - 6

5 0
3 years ago
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How many different ways are there to choose a subset of the set {1,2,3,4,5,6} so that the product of the members of the subset i
zvonat [6]

You have to pick at least one even factor from the set to make an even product.

There are 3 even numbers to choose from, and we can pick up to 3 additional odd numbers.

For example, if we pick out 1 even number and 2 odd numbers, this can be done in

\dbinom 31 \dbinom 32 = 3\cdot3 = 9

ways. If we pick out 3 even numbers and 0 odd numbers, this can be done in

\dbinom 33 \dbinom 30 = 1\cdot1 = 1

way.

The total count is then the sum of all possible selections with at least 1 even number and between 0 and 3 odd numbers.

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where we use the binomial identity

\displaystyle \sum_{k=0}^n \binom nk = \sum_{k=0}^n \binom nk 1^{n-k} 1^k = (1+1)^n = 2^n

3 0
1 year ago
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