Answer: a. 0.6759 b. 0.3752 c. 0.1480
Step-by-step explanation:
Given : The long-distance calls made by the employees of a company are normally distributed with a mean of 6.3 minutes and a standard deviation of 2.2 minutes
i.e.
minutes
minutes
Let x be the long-distance call length.
a. The probability that a call lasts between 5 and 10 minutes will be :-

b. The probability that a call lasts more than 7 minutes. :
![P(X>7)=P(\dfrac{X-\mu}{\sigma}>\dfrac{7-6.3}{2.2})\\\\=P(Z>0.318)\ \ \ \ [z=\dfrac{X-\mu}{\sigma}]\\\\=1-P(Z](https://tex.z-dn.net/?f=P%28X%3E7%29%3DP%28%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B7-6.3%7D%7B2.2%7D%29%5C%5C%5C%5C%3DP%28Z%3E0.318%29%5C%20%5C%20%5C%20%5C%20%5Bz%3D%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-P%28Z%3C0.318%29%5C%5C%5C%5C%3D1-0.6248%5C%20%5C%20%5C%20%5C%20%5B%5Ctext%7Bby%20z-table%7D%5D%5C%5C%5C%5C%3D0.3752)
c. The probability that a call lasts more than 4 minutes. :

Answer:
5640
Step-by-step explanation:
Answer:
huh
Step-by-step explanation:
Answer: x=1/8
Step-by-step explanation:
Subtract 3 from both sides
3+ 8x=4
8x=1
Divide by 8 on both sides
x=1/8
Hope this helped! :)
A/c = 8.....a = 8c
a * c = 2 ...a = 2/c
a/b = -16 ...a = -16b
a * b = -1....
b/c = -0.5
2/c = 8c
2 = 8c^2
1/4 = c^2
sqrt 1/4 = c
0.5 (or 1/2) = c <===
a * c = 2
0.5a = 2
a = 2/0.5
a = 4 <===
a = -16b
4 = -16b
4/-16 = b
-1/4 (or - 0.25) = b <===