Answer:
C. 42
Explanation:
A sperm cell is a sex cell which is a haploid cell and thus has half the chromosomes of a somatic cell which is a diploid cell.
Answer:
The correct answers would be maintain chromosome number through generations and cause genetic variations by recombination.
In Meiosis a cell divides into four daughter cells all of which have half the number of chromosomes present in a parent cell.
It helps in the formation of gametes in sexually reproducing organisms.
These gametes (one from father and one from mother) fuse together to form a zygote. It re-established the chromosomal number as that of the parent.
In absence of meiosis, the chromosomal number would have doubled after each generation.
In addition, the meiosis also increases the genetic variation among the population with the help of crossing over which occurs during the pachytene stage of prophase I.
During this event, genetic information is exchanged between the non-sister chromatids of the homologous chromosomes. It produces a new combinations of genes that are different from either parent.
The answer would be C, double fertilization produces a triploid zygote and a tripped endosperm!
Hypertonic solution means the solution with a lower water potential than the cell cytoplasm, such as salt water.
When the red blood cell is put into it, since the cell has a higher water potential than the solution, water molecules will flow from the cell back into the water due to osmosis.
Osmosis is always where water molecules flow from a region of higher water potential to lower, through a semi permeable membrane (Whcih is the red blood cell membrane in this case.)
Since water flowed out of the cell, the cell lose water and shrinks.
Hypotonic solution is where the solution that has a higher water potential than the cell cytoplasm.
So when the red blood cell is put in that solution, the water will flow from the solution into the cell this time, by osmosis.
The red blood cell will then gain so much water that the cell membrane cannot hold all and therefore burst.
The true statements are:
- Substrate level phosphorylation ocvurs during Pyruvate oxidation
- 32 ATP molecules can be made by cellular respiration but only 2 ATP molecules when oxygen is lacking
- Electrons move from protein to protein due to increasing electronegativity in the electron transport chain
- ADP is phosphorylated in the matrix of the mitochondria during oxidative phosphorylation
- ATP inhibits pyruvate dehydrogenase by feedback inhibition
<h3>What is glucose oxidation?</h3>
Glucose oxidation refers to the process in the cells in which glucose molecules are oxidized to form ATP and carbon dioxide in the presence of oxygen.
The first stage of glucose oxidation is the conversion to pyruvate.
Pyruvate is oxidized to acetylCoA.
AcetylCoA enters the citric acid cycle to produce reducing equivalents, NADH for the electron transport chain.
- The true statements about pyruvate oxidation is that there is substrate level phosphorylation during the process
- When there is sufficient oxygen, 36 ATP molecules can be made (theoretically) by cellular respiration. However, when oxygen is lacking, only 2 ATP molecules are made.
- In the electron transport chain of cellular respiration, electrons move from protein to protein due to increasing electronegativity
- During oxidative phosphorylation, ADP is phosphorylated in the matrix of the mitochondria
- Aerobic respiration can be regulated by feedback inhibition of pyruvate dehydrogenase by ATP.
Learn more about pyruvate oxidation at: brainly.com/question/22565849
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