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kondor19780726 [428]
3 years ago
12

2. A car with mass 2,500 kg is travelling at 15 m/s. What is the car's kinetic energy?

Physics
1 answer:
BabaBlast [244]3 years ago
7 0

Answer:

c, 280,000J

Explanation:

You should use the equation KE (Kinetic Energy) = \frac{1}{2} mv^2

m = 2500

v = 15

KE = \frac{1}{2} * 2500 * (15)^2\\

KE = 281250 Joules.

This is consistent with the answer B, as all of the parameters given to you are rounded to 2 significant figures so naturally, the answer should also be rounded to 2 sig figs.

KE = 280,000 J

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A coffee cup calorimeter is prepared, containing 100.000 g of water (specific heat capacity = 4.184 J/g K) at initial temperatur
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Answer : The molar heat of solution for the salt is 452.9 kJ/mole

Explanation :

First we have to calculate the heat of solution.

q=m\times c\times \Delta T

where,

q = heat of solution = ?

c = specific heat of water = specific heat of solution = 4.184J/g.K=4.184J/g^oC

m = mass of solution = 107.093 g

  • Mass of solution = Mass of water + Mass of salt
  • Mass of solution = 100.000 g + 7.093 g = 107.093 g

\Delta T = change in temperature = T_2-T_1=(80.000-61.128)=18.872^oC=

Now put all the given values in the above formula, we get:

q=107.093g\times 4.184J/g^oC\times 18.872^oC

q=8456.111J=8.456kJ

Now we have to calculate the molar heat of solution for the salt, in kJ/mol.

\Delta H=\frac{q}{n}

where,

\Delta H = molar heat of solution = ?

q = heat required = 8.456 kJ

m = mass of salt = 7.093 g

Molar mass of salt = 379.984 g/mol

\text{Moles of salt}=\frac{\text{Mass of salt}}{\text{Molar mass of salt}}=\frac{7.093g}{379.984g/mole}=0.01867mole

\Delta H=\frac{8.456kJ}{0.01867mole}=452.9kJ/mole

Therefore, the molar heat of solution for the salt is 452.9 kJ/mole

4 0
3 years ago
A toroidal coil of N turns has a central radius b and a square cross section of side a. Find its self-inductance.
Xelga [282]

Answer:

L = \frac{\mu_0 N^2 (a^2)}{2\pi b}

Explanation:

As we know that magnetic field due to torroid is given as

B = \frac{\mu_0 N i}{2\pi b}

this is approximately constant magnetic field along the axis of the torroid

now the flux linked with one coil of the torroid is given as

\phi = B.A

\phi = \frac{\mu_0 N i}{2\pi b}(a^2)

now total flux of N number of coils is given as

\phi_{total} = \frac{\mu_0 N^2 i(a^2)}{2\pi b}

now we know that self inductance is the property of coil in which flux of the coil will link with the current in the coil

So we know that

L = \frac{\phi}{i}

L = \frac{\mu_0 N^2 (a^2)}{2\pi b}

3 0
3 years ago
The drawing shows a triple jump on a checkerboard, starting at the center of square A and ending on the center of square B. Each
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Answer:

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3 0
4 years ago
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