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valentinak56 [21]
3 years ago
12

Help me to solve this, please!!

Physics
1 answer:
expeople1 [14]3 years ago
8 0
C) 56 M / S IS TOP SPEED OF THE ROCK HITYING GROUND
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C a basketball player pushes into another one and they both fall to the left

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The formula for acceleration, or average acceleration, is a=(vf-vi) divided by (tf-ti) .
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A body of mass 250g is release from the top of a building. if the body hits the ground with a velocity of 4m/s, calculate th hei
Nutka1998 [239]

\purple{\maltese}\large\underline{\underline{\sf\:\: Given :}} \\

» Mass ( m ) of the body = 250 g

» final velocity of the body = 4 m/s

\\\purple{\maltese}\large\underline{\underline{\sf\:\: To \: \: Find :}}  \\

» The height of the Building= ??

\\\purple{\maltese}\large\underline{\underline{\sf\:\: Solution :}} \\ \\

★ <u>Height of the </u><u>building </u><u>by the principal of conservatio</u>n;

\\\\\begin{gathered}\purple{\maltese}\large\underline{\underline{\sf\:\: using \: formula :}} \\ \\\end{gathered}

\bigstar \: \underline{ \boxed{\sf { \pink{ \:  \frac{1}{2}  \: \: mv { }^{2} =  \: mgh \:    }}}}

\\  \: \: \underline{\textsf {Putting values \: in \: the \: \: given \: formula :}} \\

\\  \sf \implies \:  \frac{1}{2}  \: \: mv { }^{2} =  \: mgh \:     \\

\\  \sf \implies \:  \frac{v {}^{2} }{2}  \: \: =  \: gh \:     \\

\\  \sf \implies \:   h \: = \frac{v {}^{2} }{2g}  \: \: \:     \\

\\  \sf \implies \:   h \: = \frac{16 }{20}  \: \: \:     \\

\\  \sf \implies \:   h \: = 0.8  \: \: \:   m  \\

\\  \sf \implies \:   h \: = 80  \: \: \:   cm  \\

henceforth , The height of the Building is <u>0.8 m or 80 cm</u> ..!!!

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