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Strike441 [17]
3 years ago
8

Expression with parentheses..example and non-example​

Mathematics
1 answer:
Dahasolnce [82]3 years ago
4 0

Answer:

<u>With parentheses:</u>

(3 - 4)(4 + 5)/3

<u>Without parentheses:</u>

7 + 6 - 11 × 2

Hope this helps! :)

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If angle BÂD=19°<br>Find angle ACB<br>​
otez555 [7]

Answer:

<ACB = 19°

Step-by-step explanation:

<BAD is a peripheral angle, meaning the angle it intersects is twice it. This means that arc AB is 2*19 or 38. Now, <ACB is an inscribed angle because it has a vertex on the circle. An inscribed angle is half the angle it intercepts. This means <ACB is 1/2 arc AB or 19.

8 0
3 years ago
A rectangular plot is enclosed by 200 m of fencing and has an area of A square metres. Show that :
Tema [17]
The perimeter of plot is 200 m. Denote sides of plot with x and y.

P=2(x+y)&#10;\\200=2(x+y)&#10;\\100=x+y&#10;\\y=100-x

The area of plot is A=xy

a) A=xy=x(100-x)=100x-x^2

b) The area is maximal for A'=0
A'=(100x-x^2)'=100-2x
100-2x=0&#10;\\100=2x&#10;\\x=50&#10;\\&#10;\\y=100-x&#10;\\y=100-50&#10;\\y=50

The sides of rectangle are x=50 and y=50. Therefore, the area is maximal if the rectangle is a square.
5 0
4 years ago
Read 2 more answers
A rectangular lawn has a diagonal path running across it. The lawn is 10m wide and 15m long. Work out the length of the path
Kisachek [45]

Answer:

d = 18.02 m

Step-by-step explanation:

Given that,

A rectangular lawn has a diagonal path running across it. The lawn is 10m wide and 15m long.

We need to find the length of the path.

The diagonal of a rectangle can be calculated as follows :

d=\sqrt{10^2+15^2} \\\\d=18.02\ m

So, the length of the path is 18.02 m.

5 0
3 years ago
Factorize: a^2+10ab -75b^2
soldier1979 [14.2K]

Answer:

9

Step-by-step explanation:

4 0
3 years ago
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Need help with this continuity problem.
ira [324]

In order to be continuous everywhere, we only need to satisfy continuity at x=10. For that to happen, we need to have

\displaystyle\lim_{x\to10^-}f(x)=\lim_{x\to10^+}f(x)=f(10)

By the function's definition, f(10)=2(10)-2=18. Compute the limits:

\displaystyle\lim_{x\to10^-}f(x)=\lim_{x\to10}2x-2=18

\displaystyle\lim_{x\to10^+}f(x)=\lim_{x\to10}-8x+b=-80+b

So we must have

18=b-80\implies b=98

3 0
3 years ago
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