Answer: A (1.156x10(6)
Step-by-step explanation: IM DOING THE INTERIM TOOOOOO
No, i believe it’s yes hope this helps
Distribute the brackets to get all your terms and then combine like terms to simplify your expression.
(X+2)(x+2)
= x^2 + 2x + 2x + 4
= x^2 + 4x + 4
2(4 + 2x) ≥ 5x + 5
First, we will need to expand our problem. Expanding is basically removing the parentheses. To do this, we will look at the first part of the problem to begin with. 2(4 + 2x). Since parentheses usually mean multiplication, we can start with 2(4). So, 2 × 4 = 8. We'll do the same thing with 2(2), 2 × 2 = 4.
![8 + 4x \ge 5x + 5](https://tex.z-dn.net/?f=8%20%2B%204x%20%5Cge%205x%20%2B%205)
Second, our next step is to subtract 4 from each side. We are trying to get the variable (x) on one side of the problem by itself.
![8 \ge 5x + 5 - 4](https://tex.z-dn.net/?f=8%20%5Cge%205x%20%2B%205%20-%204%20)
Third, we can now simplify (5x) + 5 - (4). I put parentheses around what we are going to focus on. Subtract 5x - 4 to get 1, which can be put as the variable (x). Now we have, x + 5.
![8 \ge x + 5](https://tex.z-dn.net/?f=8%20%5Cge%20x%20%2B%205)
Fourth, let's subtract 5 from each side now. This will set up 8 - 5 which equals 3.
![3 \ge x](https://tex.z-dn.net/?f=3%20%5Cge%20x)
Fifth, we can switch sides now to get the result of this problem.
![x \le 3](https://tex.z-dn.net/?f=x%20%5Cle%203)
Answer:
Answer:
Step-by-step explanation:
13x-6y=10 (1,4)
x=1 y=4
⇒ 13*1-6*4=10
⇒ 13-24=10
⇒ -11≠10
⇒ (1,4) isn`t solution of the equation y=13x-6y
y=-3|x-5|+1 (1,-11)
x=1 y=-11
-11=-3|1-5|+1
-11=-3|-4|+1
-11=-3(4)+1
-11=-12+1
-11≡-11
⇒ (1,-11) is solution of the equation y=-3|x-5|+1