1. Area of a circle is pi(R)^2 , where R is the radius. So we can substitute:
22/7(16^2) = about 805 meters squared.
2. Let's find the area of the rectangle first.
A=LW
A= 18(10)
A= 180 cm squared.
Now the semi-Circle:
The radius of the circle is 9 (because 18/2 is 9). Now we plug in to the area formula:
22/7(9^2) = about 254 cm squared. But because that is the area of the whole circle, and we only need half of the circle, we divide that value by 2 to get:
127 cm squared for the semi-circle.
Now we add up the rectangle and semi-circle's areas:
180 + 127 = 307 cm squared as your answer.
I hope this Helps!
Answer:
see explanation
Step-by-step explanation:
To factorise the quadratic consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x term.
product = 2 × - 6 = - 12 and sum = + 11
The factors are + 12 and - 1
Use these factors to split the middle term
2x² + 12x - x - 6 = 0 ( factor the first/second and third/fourth terms )
2x(x + 6) - 1(x + 6) = 0 (factor out (x + 6) )
(x + 6)(2x - 1) = 0
equate each factor to zero and solve for x
x + 6 = 0 ⇒ x = - 6
2x - 1 = 0 ⇒ x = 
9^2 / 3(1)
81 / 3 =27
A is the answer
9514 1404 393
Answer:
88 ounces
Step-by-step explanation:
Let x represent the number of ounces of the less expensive alloy in the mix. Then the cost of the mix will be ...
6.75x +10(55) = 8(55+x)
110 = 1.25x . . . . . . subtract 440+6.75x
88 = x . . . . . . . . divide by 1.25
88 ounces of $6.75/oz silver must be used.
X, x + 1, x + 2
sum of three consecutive integers is 1 more than 2 times the smallest integer
(x) + (x + 1) + (x + 2) - 16 = 2x
3x + 3 - 16 = 2x
3x -13 = 2x
-13 = -x
13 = x
The smallest integer is 13, the second integer is 14, the third integer is 15
