Vanadium
V 1s²2s²2p⁶3s²3p⁶4s²3d³
Answeryou understand but id ont if your know the answer plz help me
Explanation:
I believe the correct answer would be the last option. All of the quantities given above contain the same number of particles. We determine this by using the avogadro's number. It represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole.
2 moles of carbon atoms ( 6.022 x 10^23 particles / mole ) = 1.20 x10^24 particles
<span>
2 moles of carbon dioxide molecules </span>( 6.022 x 10^23 particles / mole ) = 1.20 x10^24 particles<span>
2 moles of diatomic oxygen molecules </span>( 6.022 x 10^23 particles / mole ) = 1.20 x10^24 particles
As you can see, no matter what is the gas as long as they have the same number of moles, they would also have same number of particles<span />
We are given with
V = <span>2.394 x 102 mL
P = </span><span>7.20 x 102 mm of Hg
T = </span><span>78 oC
We are asked to determine the mass of the sample in milligrams
Using the ideal gas law
n = PV / RT
n = </span>7.20 x 102 mm of Hg (2.394 x 102 mL) / R (78 + 273)
Use the appropriate value for R or just convert the values to SI and use R = 8.314
Then, solve for the mass of the sample by using the MW Oxygen which is 16 g/mol
Answer:
0.020g de sulfato de plomo se requieren
La concentración de la solución diluida es de 3ppm
Explanation:
Las partes por millón (ppm) son definidas como:
miligramos soluto / 1L solución.
Si deseas preparar una solución a 100ppm de sulfato de plomo (II) necesitas 100mg de este sulfato en 1L. En 200mL = 0.200L vas a necesitar:
0.200L × (100mg / 1L) = 20mg de sulfato de plomo (II).
Como 1000mg = 1g,
20mg × (1g / 1000mg) = 0.020g de sulfato de plomo se requieren.
Ahora, se van a tomar 30mL de esta solución y se diluirán a 1000mL. Se diluye la solución:
1000mL / 30mL = 33.33 veces.
Como la solución inicial es de 100ppm, esta dilución genera una solución de concentración:
100ppm / 33.33 = 3ppm
