Does anybody know the answer to these two questions ?

Chemistry

1 answer:

kogti [31]3 years ago

5 0

A.) Hydroxide ion is the negative ion found in bases.

C.) Color change occurs during neutralization reaction.

Hope this helps!

You might be interested in

Grade 11 chemistry what happen when n hexane is heated at 600 degree celcius in pressure of a cr2O3 catalyst?

Nonamiya [84]

Answer:

For Example, When n-Hexane Is Passed Over Chromium Oxide (Cr2O3) Supported Over Alumina (Al2O3) at 600 degree Celsius, Benzene Is Produced

8 0

2 years ago

If a 12.0-g sample of radon-222 decays so that after 19 days only 0.375 g remains, what is the half-life of radon-222? 9.50 days

max2010maxim [7]

$A_{f}=A_{0}*(1/2)^{ \frac{t}{h}} 

A(f) - final amount,
A(0) -initial amount,t - time, h- half-life.
\\ \\0.375=12.0*(1/2)^{ \frac{19}{h}} 
\\ \\(0.375/12.0)=(1/2)^{ \frac{19}{h}} 
\\ \\log(0.375/12.0)=log(1/2)^{ \frac{19}{h}} 
\\ \\ \frac{19}{h}*log(1/2)= log(0.375/12.0)
\\ \\ \frac{19}{h}= \frac{log(0.375/12.0)}{log(1/2)} 
\\ \\ h= \frac{19log(1/2)}{log(0.375/12.0)} =3.80 (days)
\\ \\ h=3.80(days)
$

4 0

4 years ago

Read 2 more answers

(4) After addition of hydrochloric acid, a student removes the lower aqueous layer, extracts the aqueous phase with diethyl ethe

laiz [17]

Answer:

The student did not lose any organic product in the aqueous layer

Explanation:

From the question;

After addition of hydrochloric acid, a student removes the lower aqueous layer and extracts the aqueous phase with diethyl ether (0.5 mL).

The only possible way the student could have lose the product was if there are some basic group e.g $NH_2$ in the compound which have a tendency of forming $NH_3^+$ salt.

Also these compound could be regenerated from aqueous layer by neutralizing the aqueous layer with basic solution , for example; by using sodium hydroxide (NaOH) in which the extraction is then followed by the usage of Diethyl ether.

6 0

4 years ago

Determine the mass of butane gas that was released from the lighter and collected in the gas collection tube. Use the given belo

ruslelena [56]

There are several information's already given in the question. Based on those information's, the answer can be easily deduced.
Gas constant = 0.0821
Now
<span>PV=nRT
</span>(1.2) * (0.09) = n * (0.0821) * (297)
n = 0.00443
Mass of Butane = 32.105 - 31. 844
= 0.261
Then
Molar mass of Butane gas = 0.261/.00443
= 58.92

6 0

3 years ago

How long will a 25.00 g

charle [14.2K]

Answer:

Hope it helps.

Explanation:

It decays by beta particle emission into xenon-131. After eight days have passed, half of the atoms of any sample of iodine-131 will have decayed, and the sample will now be 50% iodine-131 and 50% xenon-131

3 0

3 years ago