Answer:
c 3 mol of Ba(OH)₂ and 1 mol of Ba₃N₂ should be interchanged
Explanation:
Ba₃N₂ + 6H₂O → 3Ba(OH)₂ + 2NH₃
n/mol: 9.2
They want to find moles of Ba₃N₂, so that should be in the numerator of the conversion factor,
Moles of Ba(OH)₂ should be in the denominator to cancel the units in 9.2 mol Ba(OH)₂,
Answer:
E. Gain of electrons
Explanation:
A reduction reaction is one part of the two concurrent reactions that take place in a redox (reduction-oxidation) reaction.
During reduction, an atom gains electrons from a donor atom, and it's oxidation number becomes smaller.
Option A is wrong because reduction does not increase oxidation state nor are neutrons involved
Option B is wrong because reduction is not a nuclear reaction (does not involve the nucleons)
Option C is wrong because reduction leads to reduction in oxidation state
Option D is wrong leads to a reduction in oxidation state when electrons are gained
Option E is correct because reduction involves gain of electrons
<span>The statement best describes the collisions of gas particles according to the kinetic-molecular theory is that the collisions of gas particles in an ideal gas are completely elastic. An expansion in the quantity of gas particles in the holder expands the recurrence of impacts with the dividers and in this manner the weight of the gas. The last propose of the motor sub-atomic hypothesis expresses that the normal active vitality of a gas molecule depends just on the temperature of the gas.</span>
Yes it’s a soluble because the carbonate should dissolve in any strong acid with much effervescence
Answer:
0.364
Explanation:
Let's do an equilibrium chart for the reaction of combustion of ammonia:
2NH₃(g) + (3/2)O₂(g) ⇄ N₂(g) + 3H₂O(g)
4.8atm 1.9atm 0 0 Initial
-2x -(3/2)x +x +3x Reacts (stoichiometry is 2:3/2:1:3)
4.8-2x 1.9-(3/2)x x 3x Equilibrium
At equilibrium the velocity of formation of the products is equal to the velocity of the formation of the reactants, thus the partial pressures remain constant.
If pN₂ = 0.63 atm, x = 0.63 atm, thus, at equilibrium
pNH₃ = 4.8 - 2*0.63 = 3.54 atm
pO₂ = 1.9 -(3/2)*0.63 = 0.955 atm
pH₂O = 3*0.63 = 1.89 atm
The pressure equilibrium constant (Kp) is calculated with the partial pressure of the gases substances:
Kp = [(pN₂)*(pH₂O)³]/[(pNH₃)²*
]
Kp = [0.63*(1.89)³]/[(3.54)²*
]
Kp = 4.2533/11.6953
Kp = 0.364
