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3 years ago

64 children attended a computer course. 5/8 of them were girls. How many more girls than boys were there?

Mathematics

2 answers:

Harlamova29_29 [7]3 years ago

7 0

There were a total of 28 more girls than boys.

Kruka [31]3 years ago

6 0

If the total is 64, to calculate the girls, just multiply 64 by 5/8, and you get 40 girls. so the number of boys is actually 8-5/8, which is 3/8, so in total there r 24 boys.
so 40 - 24 makes there r 16 more girls

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Step-by-step explanation:

Hi there!

What we need to know:

Slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when x is 0)

1) Determine the slope (m)

$m=\frac{y_2-y_1}{x_2-x_1}$ where two points that the line passes through are $(x_1,y_1)$ and $(x_2,y_2)$

Plug in the given points (1,-3) and (-3,17)

$=\frac{17-(-3)}{-3-1}\\=\frac{17+3}{-3-1}\\=\frac{20}{-4}\\=-5$

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Plug in one of the given points and solve for b

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Add 5 to both sides of the equation to isolate b

$-3+5=-5+b+5\\2=b$

Therefore, the y-intercept of the equation is 2. Plug this back into $y=-5x+b$ :

$y=-5x+2$

I hope this helps!

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