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wlad13 [49]
3 years ago
13

I don’t feel like doing the science so can somebody help I’ll mark brainlyest

Biology
1 answer:
vampirchik [111]3 years ago
4 0

Answer:

hmmm

Explanation:

You might be interested in
Please help me asap!!!
Bezzdna [24]

Answer:

plants need sunlight. (animals dont)

BOTH, plants and animals need nutrients.

BOTH, plants and animals need oxygen.

BOTH, plants and animals need a suitable temperature.

Plants and animals need water.

BOTH need carbon dioxide

7 0
3 years ago
The human MN blood type is determined by two codominant alleles, L(M) and L(N). The frequency of L(M) in Eskimos on a small Arct
tatiyna

Answer:

(a) Frequency of M = 0.64

    Frequency of N = 0.04

    Frequency of MN= 0.32

(b)  Expected frequencies of M = 0.648

     Expected frequencies of MN = 0.304

     Expected frequencies of N =  0.048

Explanation:

(a) If random mating takes place in the population, then  the expected frequencies are

f(L(M)) = p = 0.8

F(L(N)) = q

q= 1 - p

= 1 - 0.8

= 0.2

Frequency of M = p^2 = ( 0.8)^2 = 0.64

Frequency of N = q^2 = (1-p)^2 = (1 - 0.8)^2 = (0.2)^2 = 0.04

Frequency of MN = 2pq = 2 * 0.8 * 0.2 = 0.32

(b)

F = inbreeding coefficient = 0.05

f(L(M)L(M)) = p^2 + Fpq = (0.8)^2 + 0.05 * 0.8 * 0.2 = 0.648

f(L(M)L(N)) = 2 pq - 2Fpq = 2 * 0.8 * 0.2 - ( 2 * 0.05 * 0.8 * 0.2) = 0.304

f(L(N)L(N)) = q^2 + Fpq = (0.2)^2 + ( 0.05 * 0.8 * 0.2) = 0.048

5 0
2 years ago
What is the best thing to do when you're depressed?
Elina [12.6K]

Answer:

Eat a cookie then yeah.

yea

4 0
2 years ago
Read 2 more answers
let A and a represent dominant and recessive alleles whos respective frequencies are p and q in a given interbreeding population
lesantik [10]

Answer:

A) 48 %

B) 18 %

Explanation:

A) Given

Frequency of individuals in the population having recessive phenotypes = 16%

Frequency of individuals in the population having recessive phenotypes is represented by q^2

q^ 2 = 0.16\\q= \sqrt{0.16}\\ q = 0.4

Thus frequency of recessive genes is equal to 40%

frequency of dominant genes is equal to

p = 1-q\\= 1-0.4\\= 0.6

Now,

p^2 + q^2+2pq = 1\\2pq = 1-0.16-0.36\\2pq = 0.48

48 % of genes exist in the heterozygous condition

B.

Frequency of individuals in the population having recessive phenotypes = 1%

Frequency of individuals in the population having recessive phenotypes is represented by q^2

q^ 2 = 0.01\\q= \sqrt{0.01}\\ q = 0.1

Thus frequency of recessive genes is equal to 10%

frequency of dominant genes is equal to

p = 1-q\\= 1-0.1\\= 0.9

Now,

p^2 + q^2+2pq = 1\\2pq = 1-0.01-0.81\\2pq = 0.18

18 % of genes exist in the heterozygous condition

8 0
3 years ago
The height of a yarrow plant (Achillea millefolium) depends on its genotype and the altitude at which it is raised. Suppose that
77julia77 [94]

Answer:

       The right answer to this question is B. Norm of reaction for height.

Explanation:

       Norm of reaction is a type of study that focus on a single genotype, and how it'll influence the phenotype of the species in different environments. In this case, we're studying Achillea Millefolium, that according to the question, depends on one specific genotype to be or not to be tall. Through this information given by the question, we can be sure that this is a norm of reaction, because after that, to check if the plant is tall of not, we test it on different environments, confirming the norm of reaction again.

7 0
3 years ago
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