We will assume that the solvent is water. So, if we have 100 grams of the solution, 19 grams will be sodium hydroxide, while the remaining 81 grams will be water.
The molar weight of sodium hydroxide, NaOH, is 40. The molar weight of water is 18. Finding the moles of each:
NaOH: 19 / 40 = 0.475
Water: 81 / 18 = 4.5
Total moles present: 4.5 + 0.475 = 4.975 moles
The mole fraction of NaOH is: 0.475 / 4.975 = 0.0955
