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Ira Lisetskai [31]
3 years ago
7

Find the missing side of each triangle

Mathematics
1 answer:
Troyanec [42]3 years ago
3 0

Answer:

2 km

Step-by-step explanation:

hypotenuse (h) = 10.6 km

perpendicular (p) = 10.4 km

base (b) = ?

We know by using Pythagoras theorem

b = √h² - p²

= √ (10.6)² - (10.4) ²

= √ 4.2

= 2 km

Hope it will help :)

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Six less than six timesa number is 12
vovangra [49]
Six (6) less than (subtraction) six (6) times (multiplication) a number (n) is (=) 12.

6n - 6 = 12  

To solve, add 6 to both sides

6n = 18   Dviide both sides by 6
  n = 3
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WILL MARK YOU BRAINLIEST JUST GIVE THE ANSWER!!
Igoryamba
Your answer would be the second option
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The managers of 21 supermarkets counted the number of cars in their parking lots on the same day. The results are shown in the l
mixer [17]

The IQR is 42.5

Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: (\frac{n+1}{2}) th\ term

Putting n=21

(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term

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So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

<u>For First Half:</u>

98, 100, 101, 102, <u>108, 109</u>, 111,118, 129, 132

Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5

<u>For Second Half:</u>

135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151

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<u>Interquartile Range:</u>

IQR = Q_3-Q_1\\= 151-108.5\\=42.5

Hence,

The IQR is 42.5

Keywords: Median, IQR

Learn more about median at:

  • brainly.com/question/10940255
  • brainly.com/question/10941043

#LearnwithBrianly

7 0
3 years ago
This is part two of the problem
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Answer:

Area original = 8

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True

Step-by-step explanation:

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Answer:

it would be A

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