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Bas_tet [7]
2 years ago
6

PLSS HELP IM BEING TIMED PLSSS

Mathematics
1 answer:
lina2011 [118]2 years ago
8 0

Answer:

Right triangle

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2,3,5,9,17 what’s the pattern?
azamat

2,3,5,9,17 what’s the pattern?

The pattern is multiply by 2 then subtract 1

2 x 2 - 1 = 4 - 1 = 3

3 x 2 - 1 = 6 - 1 = 5

5 x 2 - 1 = 10 - 1 = 9

9 x 2 - 1 = 18 - 1 = 17

17 x 2 - 1 = 34 - 1 = 33

33 x 2 - 1 = 66 - 1 = 65

65 x 2 - 1 = 130 - 1 = 129

7 0
2 years ago
The volume of a large aquarium is 210 yd. It is 3 yd wide and 2
Pavel [41]

Length of the aquarium is 35 yd

Step-by-step explanation:

  • Step 1: Volume of the aquarium = 210 yd³ given by Volume = length × width × height. Width = 3 yd and Height = 2 yd

Length = Volume/Width × Height

            = 210/3 × 2 = 210/6

            = 35 yd

5 0
3 years ago
(2*)2-3×2*+2=0<br>4m-15°(×)m+75°​
Valentin [98]

Answer:

First, we write the augmented matrix.

⎡

⎢

⎣

1

−

1

1

2

3

−

1

3

−

2

−

9

|

8

−

2

9

⎤

⎥

⎦

Next, we perform row operations to obtain row-echelon form.

−

2

R

1

+

R

2

=

R

2

→

⎡

⎢

⎣

1

−

1

1

0

5

−

3

3

−

2

−

9

|

8

−

18

9

⎤

⎥

⎦

−

3

R

1

+

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

5

−

3

0

1

−

12

|

8

−

18

−

15

⎤

⎥

⎦

The easiest way to obtain a 1 in row 2 of column 1 is to interchange \displaystyle {R}_{2}R

​2

​​  and \displaystyle {R}_{3}R

​3

​​ .

Interchange

R

2

and

R

3

→

⎡

⎢

⎣

1

−

1

1

8

0

1

−

12

−

15

0

5

−

3

−

18

⎤

⎥

⎦

Then

−

5

R

2

+

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

1

−

12

0

0

57

|

8

−

15

57

⎤

⎥

⎦

−

1

57

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

1

−

12

0

0

1

|

8

−

15

1

⎤

⎥

⎦

The last matrix represents the equivalent system.

x

−

y

+

z

=

8

y

−

12

z

=

−

15

z

=

1

Using back-substitution, we obtain the solution as \displaystyle \left(4,-3,1\right)(4,−3,1).First, we write the augmented matrix.

⎡

⎢

⎣

1

−

1

1

2

3

−

1

3

−

2

−

9

|

8

−

2

9

⎤

⎥

⎦

Next, we perform row operations to obtain row-echelon form.

−

2

R

1

+

R

2

=

R

2

→

⎡

⎢

⎣

1

−

1

1

0

5

−

3

3

−

2

−

9

|

8

−

18

9

⎤

⎥

⎦

−

3

R

1

+

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

5

−

3

0

1

−

12

|

8

−

18

−

15

⎤

⎥

⎦

The easiest way to obtain a 1 in row 2 of column 1 is to interchange \displaystyle {R}_{2}R

​2

​​  and \displaystyle {R}_{3}R

​3

​​ .

Interchange

R

2

and

R

3

→

⎡

⎢

⎣

1

−

1

1

8

0

1

−

12

−

15

0

5

−

3

−

18

⎤

⎥

⎦

Then

−

5

R

2

+

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

1

−

12

0

0

57

|

8

−

15

57

⎤

⎥

⎦

−

1

57

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

1

−

12

0

0

1

|

8

−

15

1

⎤

⎥

⎦

The last matrix represents the equivalent system.

x

−

y

+

z

=

8

y

−

12

z

=

−

15

z=1

Using back-substitution, we obtain the solution as \displaystyle \left(4,-3,1\right)(4,−3,1).

7 0
2 years ago
Cassie took 2 quizzes last week. She scored the same in each quiz.
ololo11 [35]

Answer:

since her score was -12 from being perfect

if she had scored 12 more points her score would have been perfect .

that is difference between her score and the perfect score o each quiz was <u>12</u>

8 0
3 years ago
A pizza was divided into fourths.Jack ate 1/2 of one of the fourths what part of the pizza did he eat?
Virty [35]
He ate 1/8 of the pizza
7 0
3 years ago
Read 2 more answers
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