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Gre4nikov [31]
3 years ago
14

After t seconds, a ball in the air from the ground level reaches a height of h feet given by the equation h= 144t-16t^2 . After

how many seconds will the ball hit the ground before rebounding?
Mathematics
1 answer:
Effectus [21]3 years ago
3 0
H=0
Therefore:
144t-16t²=0
t (144-16t)=0
We have two equations:
1)
t=0    (when the ball is released)
2)
144-16t=0
-16t=-144
t=-144 / -16=9  (this is the time )

Answer: the ball hit the ground in 9 s. 
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salantis [7]
To write the equation of a line, we use the equation: y = mx +b.

m is the slope of the line, which can be calculated using the equation:
m = (y2 - y1)/(x2 - x1) 
We can choose any two points on the line to put into this equation. The red dots are at (0,0) and (-6,-2), so we will use those, but you would get the same answer by using any other pair of coordinates on the blue line.
m = (-2 - 0)/(-6 - 0) = 2/6 = 1/3

b is the y-intercept of the line. The y-intercept is the y-coordinate when the line crosses the y-axis. It crosses the y-axis at (0,0), so the y-intercept is 0.


Now, we plug our values back into the full equation to get the equation of the line.
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6 0
3 years ago
Read 2 more answers
Mr. Nelson lost one of his students' test
amid [387]

Complete question :

Mr. Nelson lost one of his students' test papers. He knows that the other 4 students scored as follows: 60, 62, 56, 57. He also knows that the average score is 59.2. What is the score on the missing paper?

Answer:

61

Step-by-step explanation:

Given the following :

Total number of students = 4 + 1 missing = 5

Score on the four avaliable papers = 60, 62, 56, 57

Average score of the 5 papers = 59.2

Score on missing paper :

Sum of each score / number of papers

Sum of each score = sum of available scores + missing score

Let missing score = m

(60 + 62 + 56 + 57 + m) = 235 + m

Recall:

Average = total sum / number of observations

Hence,

59.2 = (235 + m) / 5

59.2 × 5 = 235 + m

296 = 235 + m

m = 296 - 235

m = 61

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6 0
2 years ago
Imagine the fire department had to evacuate the 25th floor of an office building. For firefighters to safely reach people at thi
joja [24]

Answer:

Check Explanation

Step-by-step explanation:

Some information required to answer this question is missing, but on a general basis, here goes the carefully researched response.

Majority of popular truck ladders are about 75 to 105 feet long. There are special truck ladders that reach up to 125 feet.

The length of a truck ladder is naturally limited by weight. The weight has to not be too much so that the truck can still move at a good enough speed on the roads. The weight of these ladders are primarily dependent on the strength of the metal used to make them.

At the top of these ladders, on a windy day, eind interference can cause the ladder to move back and forth all over the place, rhereby endamgerimg lives further and using a light material because we want the truck to still be able to move, will not work because light ladders especially, are easily carried by wind.

The 105-foot aerial ladder can reach 7 to 8 floors depending on the height of the floors.

The 25th floor of an office building can be accessed using a ladder that is about 225 ft long and that simply, is not feasible at all to manufacture this ladder considering the required weight and how too far away in the air this ladder would be, there would be little or no control over this.

Hence, a more realistic solution would be an helicopter that is steadied to slowly get people out of that floor.

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Hope this Helps!!!

4 0
3 years ago
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Nana76 [90]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
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Simora [160]

Answer:

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5 0
2 years ago
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