One is the integral of e^x times cos x.
Use integration by parts.
For f(x)=1/x^2-3
Find
A) f(3)
B) f(2-h)
If f(x)=1/x^2-3, then f(3) = 1 / 3^2 - 3. The exponentiation here must be carried out first: f(3) = 1/9 - 3. Then f(3) = 1/9 - 27/9 = -26/9
If f(x)=1/x^2-3, then f(2-h) = 1 / [2-h]^2 - 3. This result may be left as is or expanded. In expanded form, we have:
1
f(2-h) = ------------------ - 3
4-4h +h^2
Answer:
Step-by-step explanation:
Try dividing the first equation by 3. The result will be identical to the second equation. Thus, we have two lines that coincide, and therefore there are an infinite number of solutions.
2(c-3)=s
because you have to subtract 3 years from sherman's age first, so you need the parentheses
