Question

The initial population of a town is 4200​, and it grows with a doubling time of 10 years. What will the population be in 8 ​years?

Answer 1

Answer:

The population in 8 years will be of 7313.

Step-by-step explanation:

Population of a town:

The population of a town, after t years, with a doubling time of n years, is given by:

$P(t) = P(0)(2)^{\frac{t}{n}}$

The initial population of a town is 4200​, and it grows with a doubling time of 10 years.

This means that $P(0) = 4200, n = 10$

So

$P(t) = 4200(2)^{\frac{t}{10}}$

What will the population be in 8 ​years?

This is P(8). So

$P(8) = 4200(2)^{\frac{8}{10}} = 4200(2)^{0.8} = 7313$

The population in 8 years will be of 7313.