Help pls, answer choices listed!!

using the distance formula d=√(x2- x1)^2 +(y2-y^1, what is the distance between point (-3,1) and point (-2,4) rounded to the nea

defon

Answer:

$d = \sqrt{(x2 - x1) + (y2 - y1)} \\ d = \sqrt{ (- 3 + 2) + (1 + - 4)} \\ d = \sqrt{ - 1 + - 3 } \\ d = \sqrt{ - 4 } \\ d = - 2$

Step-by-step explanation:

<h2>hope it helps you<3</h2>

4 0

2 years ago

mrs.eddington is buying a new big screen television. She made an initial payment of $50 and paid a total of $890 over 12 months.

Gnom [1K]

890-50=840 840/12= 70 monthly

3 0

3 years ago

In parallelogram DEFG, DH = x + 5, HF = 2y, GH = 4x-3 and HE = 4y + 1. Find the values of x and y. The diagram is not drawn to s

GalinKa [24]

Rule: The diagonals of any parallelogram bisect each other. In other words, they cut each other in half.

This means DF is cut into two equal pieces: DH and HF.
Similarly, GE is cut into two equal pieces: GH and HE.

DH = HF
x+5 = 2y
x = 2y-5

GH = HE
4x-3 = 4y+1
4(x)-3 = 4y+1
4(2y-5)-3 = 4y+1 ... x has been replaced with 2y-5
8y-20-3 = 4y+1
8y-23 = 4y+1
8y-4y = 1+23
4y = 24
y = 6

If y = 6, then x is
x = 2y-5
x = 2(6)-5
x = 12-5
x = 7

--------------------------------------------

Answers:
x = 7 and y = 6

5 0

3 years ago

What are co primes and primes Hrishiiiii pls help me

Anon25 [30]

Answer:

SEE BELOW

Step-by-step explanation:

Coprime numbers:

A Co-prime number is a set of numbers or integers which have only 1 as their common factor.

For eg: (2,3), (11,12), (99,100) and so on; they have 1 as their HCF. The sum of any two coprime numbers is always coprime with the product of the same two coprime numbers. For eg: The sum of 2 and 3 is 5 and the product of 2 and 3 is 6. Hence, 5 and 6 are coprime numbers.

Prime number

A number that can be divided exactly only by itself and 1, for example 7, 17 and 41

8 0

3 years ago

You are planning a survey of starting salaries for recent computer science majors. In a recent survey by the National Associatio

nydimaria [60]

Answer:

A sample size of 554 is needed.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So: