4x +1 = -47 I’ve been trying to find this out for a while now and I simply just can’t
1 answer:
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Q(p) = k/p^3 . . . . . . . . we want to find k
q(10) = k/10^3 = 64
k = 64,000
Revenue = q(p)*p = 64000/p^2
Cost = 150 +2q = 150 +2*64000/p^3
Profit = Revenue -Cost = 64000/p^2(1 -2/p) -150
Differentiating to find the maximum profit, we have
.. dProfit/dp = -2(64000/p^3) +6(64000/p^4) = 0
.. -1 +3/p = 0
.. p = 3
A price of $3 per unit will yield a maximum profit.
q(10) = k/10^3 = 64
k = 64,000
Revenue = q(p)*p = 64000/p^2
Cost = 150 +2q = 150 +2*64000/p^3
Profit = Revenue -Cost = 64000/p^2(1 -2/p) -150
Differentiating to find the maximum profit, we have
.. dProfit/dp = -2(64000/p^3) +6(64000/p^4) = 0
.. -1 +3/p = 0
.. p = 3
A price of $3 per unit will yield a maximum profit.
Answer:
the width of sue's interval will be narrower than javier's.
Step-by-step explanation:
in this problem, i do believe that sue's interval will be more narrow. in the formula,
p-hat ± ,
a larger "n" value will lead to a smaller standard error. given that the population proportion is the same for both, and the sample size is the only difference, the standard error of sue's interval will be smaller than javier's, therefore making her whole confidence interval smaller.
again, i do believe this is correct, this is what i have in my AP stat notes. hope this helps!