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zimovet [89]
3 years ago
12

Given: QD ≅ UA, ∠QDA ≅ ∠UAD Prove: △QDA ≅ △UAD

Mathematics
1 answer:
scoundrel [369]3 years ago
8 0

Answer:

Proof :- In triangle QDA and UAD

1. QD=UA (GIVEN)

2. ANGEL QDA=UAD (GIVEN)

3. DA =AD ( COMMAN BASE)

THEREFORE, TRIANGLE QDA IS CONGRUENT TO UAD (BY SAS RULE)

HENCE PROVED...

THANK YOU......

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Simplify the following expression.( Fraction form)<br><br> 7-5/6 * 7-7/6
Ipatiy [6.2K]

Answer:

1295/36

Step-by-step explanation:

the statement tell us:

(7-(5/6))*(7-(7/6))

we have:

(7-(5/6))=((6*7)-5)/6=(42-5)/6=37/6

and we have:

(7-(7/6))=((6*7)-7)/6=(42-7)/6=35/6

we need multiply both terms:

(37/6)*(35/6)=(37*35)/(6*6)

finally we have

1295/36

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3 years ago
When you start from a given set of rules and conditions and determine what must be true you are using _ reasoning
asambeis [7]

Answer:

Deductive

Step-by-step explanation:

4 0
3 years ago
This is 70 points I will report anyone who answers wrong just for points! I will be asking TWO questions Please answer correctly
Ratling [72]




QUESTION 1: In these type of question, the easiest way to get the answer is try to plug in the x and y values from the options given in the equation given, So in the first question all the choice except C are more then 14 if you plug in x and y's, for eg, if you plug in x = 3 and y = 2 , you get (3+3)2 = 14 6 x 2 = 14 12 is not equal to 14, so this eliminates this choice but if you chose C you get, (11+3)1 = 14 14 = 14 so this makes C the solution for first question and for the second question do the same thing, and the answer will be D. Hope this helps




QUESTION 2: 5xy + 9 = 44

5xy = 35

xy = 7

solution pairs are:

C. (1, 7) and (7, 1)

not mentioned: (-1.-7) and (-7, -1)






Hope this helps



Plzz don't forget to rate and thanks me


8 0
3 years ago
An object in a simulation accelerates
notsponge [240]

Observe the graph below. This graph represents the scenario.

The question is ill formated, the complete question is

In a simulation, a moving object accelerates from rest to 4 meters per second in 2 seconds. For the following three seconds, it increases linearly until it reaches a speed of 10 meters per second. Following three seconds at that speed (acceleration = 0), the item progressively decelerates until it comes to rest two seconds later. Draw the graph of this scenario for 10 seconds?

I'll describe how the graph may show.

It will move diagonally upward from time 0 to 2 seconds until it reaches the y axis at a speed of 4 m/s.

Then, from 2 to 5, the position will move up diagonally until it reaches the y axis at a speed of 10 m/s.

The next 5 to 8 seconds will be horizontal.

After that, it will descend diagonally.

Observe the graph below. This graph represents the scenario.

Learn more about Acceleration here-

brainly.com/question/21509870

#SPJ10

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For the numbers 2 through 9 on a telephone keypad, draw two mapping diagrams: one mapping numbers
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Look it up on quizzes
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