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sergeinik [125]
2 years ago
10

Tell me how you solve this and ill mark you brainlist

Mathematics
2 answers:
Greeley [361]2 years ago
8 0

Answer:

5 years

T= 100× I = 100×10

P×R= 100× 2= 500

Remove the zeros = 5years

Nataly [62]2 years ago
4 0

Step-by-step explanation:

use this formula

:))))))

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Simon calculated the volume of the prism. His work is shown here. area of base = B = 1 2 bh = 1 2 (5)(13) = 32.5 m2 volume = Bh
melamori03 [73]

Answer:

Options (1) and (5) are the correct options.

Step-by-step explanation:

See attachment for the complete question.

Simon's work,

Area of the base = B =\frac{1}{2}bh = \frac{1}{2}(5)(13)=32.5 m²

Volume = Bh = 32.5(12) = 390 m³

Let's check the error's he made.

Area of the base of the triangular prism

B =\frac{1}{2}bh=\frac{1}{2}(5)(12)

B = 30 m²

Volume of the prism = (Area of the triangular base)×(Height)

V = 30 × 4

V = 120 m³

Therefore, Options (1) and (5) are the correct options.

4 0
3 years ago
3+2/5x=11-2/5<br> What is the solution
Pachacha [2.7K]

Answer:

5/53

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
I need help please answer right
joja [24]

Answer:

8.5 ft is the length, and 7 ft is the width.

Step-by-step explanation:

8.5 ft is the length

6 0
3 years ago
GIVING BRAINLIEST!! PLZ HELP ME I HAVE TO FINISH BY SIX O CLOCK!!
JulsSmile [24]
1/2 = 18 cut
Cut= 1/36
So if victor rides for time t+ 1/36
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4 0
3 years ago
PLEASE ANSWER QUICKLY
Olegator [25]

Answer:

x=3

Step-by-step explanation:

Set equations equal to each other:

x^3-3x^2+2=x^2-6x+11

Subtract two from both sides

x^3-3x^2=x^2-6x+9
Factor out x^2 from the left side

x^2(x-3)=x^2-6x+9

Factor the right side, look for two factors of 9, which add to -6, which is just -3 and-3

x^2(x-3) = (x-3)(x-3)

So as you can see here, we have both sides in factored form, and both have a factor of (x-3) on both sides, and if one of the factors is zero, then the entire thing becomes zero, since 0 * anything= zero.

this means a solution would be at x=3, since it makes the right side 0 * 0 = 0, and the left side (3)^2 * 0 = 0

It's important to notice this, since had we divided by x-3 to make the equation a quadratic, we would've excluded this real solution, because when dividing by x-3 the solution x=3 makes it 0, so we would've been dividing by zero.

So one of the real solutions is at x=3

6 0
1 year ago
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