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3 years ago

Seating 8 students in 4 seats in the front row of the school auditorium.

Mathematics

2 answers:

jek_recluse [69]3 years ago

8 0

Answer:

the only thing i can think of is multiplying there is not to much here for me to do, like 8x4=32?

Step-by-step explanation:

Rasek [7]3 years ago

8 0

Uh the students would have to share a seat? 2 per chair? What’s the question

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Problem is in the picture. HELP asap please!! I’m so confused

sashaice [31]

Answer:

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3 years ago

Read 2 more answers

Find the solution of the given initial value problems in explicit form. Determine the interval where the solutions are defined.

natali 33 [55]

Answer:

The solution of the given initial value problems in explicit form is $y=x-x^2-2$ and the solutions are defined for all real numbers.

Step-by-step explanation:

The given differential equation is

$y'=1-2x$

It can be written as

$\frac{dy}{dx}=1-2x$

Use variable separable method to solve this differential equation.

$dy=(1-2x)dx$

Integrate both the sides.

$\int dy=\int (1-2x)dx$

$y=x-2(\frac{x^2}{2})+C$ $[\because \int x^n=\frac{x^{n+1}}{n+1}]$

$y=x-x^2+C$ ... (1)

It is given that y(1) = -2. Substitute x=1 and y=-2 to find the value of C.

$-2=1-(1)^2+C$

$-2=1-1+C$

$-2=C$

The value of C is -2. Substitute C=-2 in equation (1).

$y=x-x^2-2$

Therefore the solution of the given initial value problems in explicit form is $y=x-x^2-2$ .

The solution is quadratic function, so it is defined for all real values.

Therefore the solutions are defined for all real numbers.

4 0

3 years ago

A bicycle tire has a radius of 26 inches. How many revolutions will this tire make if the bicycle is pedaled 1 mile? (Use 3.14 f

Fittoniya [83]

How far does a wheel move when it rotates once? The length of the outside of the tyre? Isn't that the same as the circumference?

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2 years ago

Construct a trapezium ABCD such that AD is parallel to BC, AB = 4.8 cm, BC = 6.8 cm, CD = 5.4 cm and ∠ABC = 60°. Measure and wri

lara31 [8.8K]

Answer:

AC = 6.05 cm

Step-by-step explanation:

We can draw two different trapeziums with the information given.

The possible drawings of the trapezium ABCD are in the image attached.

In both trapeziums, the length of AC is the same, and we can calculate this length using the law of cosines in the triangle ABC:

AC^2 = AB^2 + BC^2 - 2 * AB * BC * cos(B)

AC^2 = 4.8^2 + 6.8^2 - 2 * 4.8 * 6.8 * cos(60)

AC^2 = 23.04 + 46.24 - 65.28 * 0.5

AC^2 = 36.64

AC = 6.05 cm

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3 years ago

The length of a rectangle is five inches less than twice it’s width. If the rectangle has a perimeter of 80 inches, find the len

yawa3891 [41]

Answer:

Width of the rectangle = 15 inches

Length of the rectangle = 25 inches

Step-by-step explanation:

Let the width of the rectangle = k inches

So, the length of the rectangle = (2k -5) inches

Perimeter = 80 in

Perimeter of a rectangle = 2 (Length + Width)

⇒ 80 = 2(k + (2k -5)

or 80 = 6k - 10

⇒ 6k = 80 + 10 = 90

or k = 90 / 6

⇒ k = 15

So the width of the rectangle = k = 15 inches

And the length of the rectangle = 2k -5 = 2 x 25 - 5 = 25 inches

5 0

3 years ago