Question

In a triangle XYZ, x = 24 cm, y = 19 cm and YXZ = 62o. The magnitude of XYZ..

Answer 1

Answer:

Step-by-step explanation:

using sine formula

$\frac{sinA}{a} =\frac{sinB}{b} =\frac{sinC}{c} \\\frac{sin \angle XYZ}{19} =\frac{sin 62}{24} \\sin \angle XYZ=\frac{19}{24} \times sin 62\\\angle ~XYZ=sin^{-1}(\frac{19}{24} \times ~sin~62) \approx 44.35^\circ$