
Let's find out the gradient (Slope " m ") of line q ;



Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :


Now, plug in the value of gradient ~

here we can clearly observe that, the Area under the curve can easily be represented as :

Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q
Answer:
a, f
Step-by-step explanation:
Answer:
Step-by-step explanation:
12n2+48n=−n3−64
Step 1: Subtract -n^3-64 from both sides.
12n2+48n−(−n3−64)=−n3−64−(−n3−64)
n3+12n2+48n+64=0
Step 2: Factor left side of equation.
(n+4)(n+4)(n+4)=0
Step 3: Set factors equal to 0.
n+4=0
n=−4
The coordinates (abscissa and ordinates) of the midpoint of the line segment is the average of the abscissas and the ordinates, respectively. Therefore, the x - coordinate of the midpoint is equal to -20 + 20 or 0 by 2 which is zero. The answer is letter E.