<span>The mass of the nail would increase, because the iron is adding oxygen to its chemical composition. This would increase the overall mass. If the mass increases from 23.2g to 24.1g, then the increase would be the difference between the two masses, or 0.9g.</span>
Answer:
1.31x10¹¹ g/cm³
Explanation:
The mass of the proton is equal to the mass of the neutron, which is 1.67x10⁻²⁴ g, so the mass of the alpha particle is 4*1.67x10⁻²⁴ = 6.68x10⁻²⁴ g.
1 fm = 1.0x10⁻²³ cm, thus the radius of the alpha particle is 2.3x10⁻¹² cm. If the particle is a sphere, the volume of it is:
V = (4/3)*π*r³, where r is the radius, so:
V = (4/3)*π*(2.3x10⁻¹²)³
V = 5.1x10⁻³⁵ cm³
The density of the particle is the how mass exists per unit of volume, so, it's the mass divided by the volume:
d = 6.68x10⁻²⁴/5.1x10⁻³⁵
d = 1.31x10¹¹ g/cm³
Answer:
2.50 atm
Explanation:
We have 10.4 g of DDT (solute), whose molar mass is 354.50 g/mol. The corresponding moles are:
10.4 g × (1 mol/354.50 g) = 0.0293 mol
The molarity of the solution is:
M = moles of solute / liters of solution
M = 0.0293 mol / 0.286 L
M = 0.102 M
We can find the osmotic pressure (π) using the following pressure.
π = M × R × T
where,
R: ideal gas constant
T: absolute temperature
π = M × R × T
π = 0.102 M × 0.0821 atm.L/mol.K × 298 K
π = 2.50 atm
Answer:
1.91 atm
Explanation:
Step 1: Calculate Henry's constant (k)
A gas has a solubility (C) of 2.45 g/L at a pressure (P) of 0.750 atm. These two variables are related to each other through Henry's law.
C = k × P
K = C/P
K = (2.45 g/L)/0.750 atm = 3.27 g/L.atm
Step 2: Calculate the pressure required to produce an aqueous solution containing 6.25 g/L of this gas at constant temperature.
We have C = 6.25 g/L and k = 3.27 g/L.atm. The required pressure is:
C = k × P
P = C/k
P = (6.25 g/L)/(3.27 g/L.atm) = 1.91 atm
This answer is C hope this helped
