Answer:
For a volume of 1 liter, we have a total mass of 220 grams of CaCl2 ( Option A)
Explanation:
<u>Step 1: </u>Given data
The concentration of the solution we want to make is 2M
2M = 2 moles/ L So the volume = 1L
The molar mass of CaCl2 is = 40 + 2*35 = 110g/mole
<u>Step 2:</u> Calculate number of moles
If we consider the volume = 1 L then for a concentration of 2M, this means the number of moles is 2
<u>Step 3:</u> Calculate mass
The molar mass of CaCl2 = 110 g/mole
This means 110 grams per 1 mole
for 2 moles the mass is 220 grams
This means that for a volume of 1 liter, we have a total mass of 220 grams of CaCl2
Examining the given reaction:
Li2O + H2O ........> 2LiOH
we find that, 1 mole of Li2O is required to react with one mole of H2O in order to produce two moles of LiOH.
Therefore, the ration between the required Li2O and H2O is 1:1
Based on this, 2.2 moles of H2O (water) are required to react with 2.2 moles of Li2O
The answer is D: Salt and Water
Answer:
So, for 1 I am most certain it has to be Organized so C. And for 2 that would be true if my brain isn't failing me- I hope this helps!
Explanation: