The molarity of the solution of H₃PO₄ needed to neutralize the KOH solution is 0.35 M
<h3>Balanced equation </h3>
H₃PO₄ + 3KOH —> K₃PO₄ + 3H₂O
From the balanced equation above,
- The mole ratio of the acid, H₃PO₄ (nA) = 1
- The mole ratio of the base, KOH (nB) = 3
<h3>How to determine the molarity of H₃PO₄ </h3>
- Volume of acid, H₃PO₄ (Va) = 10.2 mL
- Molarity of base, Ca(OH)₂ (Mb) = 0.2 M
- Volume of base, Ca(OH)₂ (Vb) = 53.5 mL
- Molarity of acid, H₃PO₄ (Ma) =?
MaVa / MbVb = nA / nB
(Ma × 10.2) / (0.2 × 53.5) = 1 / 3
(Ma × 10.2) / 10.7 = 1 / 3
Cross multiply
Ma × 10.2 × 3 = 10.7
Ma × 30.6 = 10.7
Divide both side by 30.6
Ma = 10.7 / 30.6
Ma = 0.35 M
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Blue has a shorter wave length
D) 710 g
Step by Step:
Multiply 2.5 L by 2.0 M to solve for moles
2 mol/L • 2.5 L= 5 mol
Find formula weight of sodium sulfate
Na2SO4-142.04 g/mol
Na- 2(22.99)=45.98
S-32.06
O-4(16)=64
Multiply miles by formula weight
5 mole • 142.04 g/mol=710.2 g
Answer:
Explanation:
Salicylic Acid:
Salicylic Acid is an hydroxy acid that is found as a natural compound in plants. It's IUPAC name is 2-hydroxybenzoic acid. Salicylic acid has an odorless white to light tan solid color. It sinks and mixes very slow with water.
Acid: An acid is a substance that produce hydrogen ion or proton when dissolved in water
Base: A base is a substance that will neutralize an acid to yield salt and water
Conjugate Base: This is a substance formed when an acid loses an hydrogen ion or proton when it dissolved in water.
Conjugate Acid: This is a substance formed when a base accept a proton from from any acid, when it dissolved in water.
Reaction between salicylic acid and potassium hydroxide
HOC₆H₄COOH(aq) + KOH(aq) ⇄ HOC₆H₄COOK(aq) + H₂O(l)
Acid ⇒ HOC₆H₄COOH (salicylic acid)
Base ⇒ KOH (potassium hydroxide)
Conjugate acid ⇒ H₂O (water)
conjugate base ⇒ HOC₆H₄COOK ( 2-hydroxypotasium benzoate)
