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Gwar [14]
2 years ago
9

B) 5z - 1 when z = 6 2

Mathematics
1 answer:
gogolik [260]2 years ago
7 0

Answer:

309

Step-by-step explanation:

5z-1, z=62

5(62)-1

310 - 1

309

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Find the dimensions of a rectangle with perimeter 112 m whose area is as large as possible. step 1 if a rectangle has dimensions
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Please use the solution below:
Let P = perimeter, A = area
As provided above, a = xy and 
We know that the formula to solve for the perimeter of a rectangle is P = 2x + 2y. Using the given 112m, we can solve the perimeter using the formula:
112 = 2x + 2y
56 = x + y

x = 56-y or y = 56-x
Let's solve the perimeter in terms of y using the formula below:
A = (56-y)(y)
Find the derivative of A = 56-y^2 to get the value of y.
dA/dy = 56-2y = 0
y = 56/2
y = 28
To find X, substitute the value of y in the equation x = 56 - y. 
x = 56 - 28
Therefore, x = 28.
We can conclude that the figure is not a rectangle but a square.
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Check the picture below.

bearing in mind that the slope goes by different names

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