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inysia [295]
3 years ago
7

Coach Burns charted the change in his runners’ 5K times from the first race of the year to the second race of the year. Which st

udent improved the most by decreasing the time needed to run the race? PLEASE HELP IM ON A EXAM!!!
Mathematics
2 answers:
Alecsey [184]3 years ago
8 0

Answer:

student a

Step-by-step explanation:

i just took the exam

Andrews [41]3 years ago
4 0

Answer:

Student a

Step-by-step explanation:

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a sewing club is making a quilt consisting of 25 squares with each side measuring 30cm.if the quilt has 5 rows and 5 columns .de
LenKa [72]
To find the length of the sides of the quilt multiply the length of each square by how many squares make up that side
30 cm · 5 squares = 150 cm  (this is for both length and width because this quilt is a square)
For a square, perimeter=4·side, or all sides added together
p=4·150cm
p=600cm
Area of a square is length · width
A=150 cm·150 cm
A=22,500 cm²
3 0
3 years ago
Find the equation of the line whose slope is -3 and which passes through the point (-5, 3)
nadezda [96]

Answer:

y=-3x-12

Step-by-step explanation:

Plug into equation y=mx+b

3=(-3)-5+b

Simplify

3=15+b

Subtract 15 from both sides

-12=b

Add slope and y-intercept into base equation

y=-3x-12

4 0
3 years ago
For an angle θ, tan(θ) is a negative number. Which quadrants might θ be in?
Klio2033 [76]

So for this question, we're asked to find the quadrant in which the angle of data lies and were given to conditions were given. Sign of data is less than zero, and we're given that tangent of data is also less than zero. Now I have an acronym to remember which Trig functions air positive in each quadrant. . And in the first quadrant we have that all the trig functions are positive. In the second quadrant, we have that sign and co seeking are positive. And the third quadrant we have tangent and co tangent are positive. And in the final quadrant, Fourth Quadrant we have co sign and seeking are positive. So our first condition says the sign of data is less than zero. Of course, that means it's negative, so it cannot be quadrant one or quadrant two. It can't be those because here in Quadrant one, we have that all the trick functions air positive and the second quadrant we have that sign. If data is a positive, so we're between Squadron three and quadrant four now. The second condition says the tangent of data is also less than zero now in Quadrant three. We have that tangent of data is positive, so it cannot be quadrant three, so our r final answer is quadrant four, where co sign and seek in are positive.  

4 0
2 years ago
Read 2 more answers
Please help me out :P
Veseljchak [2.6K]

cos θ = \frac{-4\sqrt{65} }{65}, sin θ = \frac{-7\sqrt{65} }{65}, cot  θ  = 4/7, sec  θ = \frac{-\sqrt{65} }{4}, cosec  θ  = \frac{-\sqrt{65} }{7}

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = \sqrt{7^{2} + 4^{2} } = \sqrt{49+16} = \sqrt{65}

sin θ = opposite/ hyp = \frac{7}{\sqrt{65} }

Rationalize, \frac{7}{\sqrt{65} } x \frac{\sqrt{65} }{\sqrt{65} } = \frac{7\sqrt{65} }{65}

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - \frac{7\sqrt{65} }{65}

cos   θ  = adj/hyp = \frac{4}{\sqrt{65} }

By rationalizing and knowing that cos  θ  is negative, cos θ  = -\frac{-4\sqrt{65} }{65}

cot θ  = 1/tan θ  = 1/7/4 = 4/7

sec θ  = 1/cos θ  = 1/\frac{4}{\sqrt{65} } = -\frac{-\sqrt{65} }{4}

cosec θ  = 1/sin θ  = 1/\frac{\sqrt{65} }{7} = \frac{-\sqrt{65} }{7}

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0
1 year ago
1.Mr. Bowen’s test is normally distributed with a mean of 75 and a standard deviation of 3 points.
lianna [129]

Answer:

2.28%

Step-by-step explanation:

Mr. bowens test is normally distributed with a mean (μ) of 75 and a standard deviation (σ) of 3 points.

The z score is used in probability to show how many standard deviation is a raw score below or above the mean. The formula for the z score (z) is given by:

z=\frac{x-\mu}{\sigma}

For a raw score (x) of 81 points, the z score can be calculated by:

z=\frac{x-\mu}{\sigma}=\frac{81-75}{3}=2

Therefore from the normal probability distribution table, the probability that a randomly selected score is greater than 81 can be given as:

P(x > 81) = P(z > 2) = 1 - P(z < 2) = 1 - 0.9772 = 0.0228 = 2.28%

7 0
3 years ago
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