Help please x=6 x= square root 80 x=12 x= square root 164
1 answer:
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Given:
The function is
It defined on the interval -8 ≤ x ≤ 8.
To find:
The intervals on which the function is increasing and the interval on which decreasing.
Step-by-step explanation:
We have,
Differentiate with respect to x.
For turning point f'(x)=0.
Now, 0 divides the interval -8 ≤ x ≤ 8 in two parts [-8,0] and [0,8]
For interval [-8,0], f'(x)>0, it means increasing.
For interval [0,8], f'(x)<0, it means decreasing.
Therefore, the function is increasing on the interval [-8,0] and decreasing on the interval [0,8].